在C ++中将文件中的每个单词读入char数组

Question

使用ifstream()读取文件然后将每个单词存储在char数组中的正确方法是什么？ 该char数组最终将用于将当前单词输入到哈希表中。

我的代码：

int main()
{
  int array_size = 4096; 
    char * filecontents = new char[array_size]; 
    char * word = new char[16];
    int position = 0; 
    ifstream fin("Dict.txt"); 

  if(fin.is_open())
    {

    cout << "File Opened successfully" << endl;
        while(!fin.eof() && position < array_size)
        {
            fin.get(filecontents[position]); 
            position++;
        }
        filecontents[position-1] = '\0';

        for(int i = 0; filecontents[i] != '\0'; i++)
        {
            word[i] = filecontents[i];
            //insert into hash table
            word[i] = ' ';

        }
        cout << endl;
    }
    else 
    {
        cout << "File could not be opened." << endl;
    }
    system("pause");
    return 0;
}

Answer 1

除非绝对必要，否则不要使用char数组。 将它们读取为字符串，然后将字符串放入哈希表中。 如果您没有哈希表，我可以推荐std :: set吗？ 可能恰好符合您的需求。

阅读的东西。 试试看：

int main()
{
    ifstream fin("Dict.txt");
    set<string> dict;  // using set as a hashtable place holder.

    if (fin.is_open())
    {
        cout << "File Opened successfully" << endl;
        string word;
        while (getline(fin, word, '\0'))
        {  /* getline normally gets lines until the file can't be read, 
                but you can swap looking for EOL with pretty much anything 
                else. Null in this case because OP was looking for null */
           //insert into hash table
            dict.insert(word); //putting word into set
        }
        cout << endl;
    }
    else
    {
        cout << "File could not be opened." << endl;
    }
    system("pause"); // recommend something like cin >> some_junk_variable
    return 0;
}