Yii2用户模型与关系表

Question

我是Yii的新手，我的用户和登录系统有问题。 我应该使用3个表进行登录检查，但是当我使用自定义查询时，我会遇到

"Argument 1 passed to yii\\web\\User::login() must implement interface yii\\web\\IdentityInterface, ActiveQuery given"

我的桌子就像：

• user : user_id, name, family, birthday, ...
• email : email_user_fk, email_addr, email_active, email_cdt
• passwd : passwd_user_fk, passwd_hashed, passwd_active, passwd_cdt

和我的查询是这样的： SELECT user.user_id, email.email_addr, email.email_active, passwd.passwd_hashed, passwd_passwd_active , ... FROM user JOIN email ON user.user_id = email.email_user_fk JOIN passwd ON user.user_id = passwd.passwd_user_fk WHERE email.email_addr = :email

请问有什么主意吗？

class User extends ActiveRecord implements IdentityInterface
{
    const STATUS_DELETED = 0;
    const STATUS_ACTIVE = 10;

    /**
     * @inheritdoc
     */
    public static function tableName()
    {
        return 'user';
    }

    public static function primaryKey(){
        return 'user_id';
    }

    /**
     * @inheritdoc
     */
    public function behaviors()
    {
        return [
            TimestampBehavior::className(),
        ];
    }


    /**
     * @inheritdoc
     */
    public static function find

    Identity($id)
        {
        return static::findOne(['id' => $id, 'status' => self::STATUS_ACTIVE]);
    }

    /**
     * @inheritdoc
     */
    public static function findIdentityByAccessToken($token, $type = null)
    {
        throw new NotSupportedException('"findIdentityByAccessToken" is not implemented.');
    }

    /**
     * Finds user by username
     *
     * @param string $username
     * @return static|null
     */
    public static function findByUsername($username)
    {
        return static::findOne(['email' => $username]);
    }

    public static function findByEmail($email)
    {
        return User::find()
            ->joinWith(['emails'])
            ->where("email.email_address = 'me@mail.com' ")
            ->one();
    }

    public static function findByMobile($email)
    {
        return User::find()
            ->joinWith(['mobiles'])
            ->where("mobile.mobile_address = '0931515124' ")
            ->one();
    }


    /**
     * Finds user by password reset token
     *
     * @param string $token password reset token
     * @return static|null
     */
    public static function findByPasswordResetToken($token)
    {
        if (!static::isPasswordResetTokenValid($token)) {
            return null;
        }

        return static::findOne([
            'password_reset_token' => $token,
            'status' => self::STATUS_ACTIVE,
        ]);
    }

    /**
     * Finds out if password reset token is valid
     *
     * @param string $token password reset token
     * @return boolean
     */
    public static function isPasswordResetTokenValid($token)
    {
        if (empty($token)) {
            return false;
        }
        $expire = Yii::$app->params['user.passwordResetTokenExpire'];
        $parts = explode('_', $token);
        $timestamp = (int) end($parts);
        return $timestamp + $expire >= time();
    }

    /**
     * @inheritdoc
     */
    public function getId()
    {
        return $this->getPrimaryKey();
    }

    /**
     * @inheritdoc
     */
    public function getAuthKey()
    {
        return $this->auth_key;
    }

    /**
     * @inheritdoc
     */
    public function validateAuthKey($authKey)
    {
        return $this->getAuthKey() === $authKey;
    }

    /**
     * Validates password
     *
     * @param string $password password to validate
     * @return boolean if password provided is valid for current user
     */
    public function validatePassword($password)
    {
        return Yii::$app->security->validatePassword($password, $this->password_hash);
    }

    /**
     * Generates password hash from password and sets it to the model
     *
     * @param string $password
     */
    public function setPassword($password)
    {
        $this->password_hash = Yii::$app->security->generatePasswordHash($password);
    }

    /**
     * Generates "remember me" authentication key
     */
    public function generateAuthKey()
    {
        $this->auth_key = Yii::$app->security->generateRandomString();
    }

    /**
     * Generates new password reset token
     */
    public function generatePasswordResetToken()
    {
        $this->password_reset_token = Yii::$app->security->generateRandomString() . '_' . time();
    }

    /**
     * Removes password reset token
     */
    public function removePasswordResetToken()
    {
        $this->password_reset_token = null;
    }

    public function rules()
    {
        return [
            [['user_name', 'user_family', 'user_birthday'], 'required'],
            [['user_gender', 'city_id_fk', 'user_status'], 'integer'],
            [['user_birthday', 'user_cdt'], 'safe'],
            [['user_name'], 'string', 'max' => 32],
            [['user_family'], 'string', 'max' => 48],
            [['user_tel', 'user_postcode'], 'string', 'max' => 12],
            [['user_address'], 'string', 'max' => 128],
            [['user_profile_image', 'user_cover_image'], 'string', 'max' => 256]
        ];
    }



    /**
     * @return \yii\db\ActiveQuery
     */
    public function getEmails()
    {
        return $this->hasMany(Email::className(), ['email_user_id_fk' => 'user_id']);
    }


    /**
     * @return \yii\db\ActiveQuery
     */
    public function getMobiles()
    {
        return $this->hasMany(Mobile::className(), ['mobile_user_id_fk' => 'user_id']);
    }


    /**
     * @return \yii\db\ActiveQuery
     */
    public function getPasswds()
    {
        return $this->hasMany(Passwd::className(), ['passwd_user_id_fk' => 'user_id']);
    }

}

Answer 1

该错误显示的是，在执行Yii :: $ app-> user-> login（）时，您必须传递一个将身份接口实现为参数的User对象（看来您正在传递另一种对象） ）。

此方法的作用是允许您在登录后保存来自用户的信息。 首先，用户提供用户名，然后必须从数据库中检索该用户名的信息，并使用该信息将用户对象设置为无效。 这是您必须传递给Yii :: $ app-> user-> login（）函数的对象。

在此处阅读有关User类的信息 。

在这里找到一个很好的样本。