在按钮上调用shell脚本，然后按一次并杀死它

Question

我似乎无法弄清楚调用后如何杀死python中的脚本。 有任何想法吗？

“Party.py”：

#!/usr/bin/python
import RPi.GPIO as GPIO
GPIO.setmode(GPIO.BOARD)
GPIO.setup(11,GPIO.IN, pull_up_down=GPIO.PUD_UP)
input = GPIO.input(11)
import time
import os
#initialise a previous input variable
prev_input = 1
party = 0
while True:
  #take a reading
  input = GPIO.input(11)
  #if the last reading was low and this one high, print
  if ((not prev_input) and input):
    if (party ==  0):
        os.system("./home/tim/bin/dalitest")
        party = 1
    elif (party == 1):
        #Kill the script
        party = 0
    time.sleep(2)
  #update previous input
  prev_input = input
  #slight pause to debounce
  time.sleep(0.05)

dalitest （灯光控制脚本）： http : dalitest

此处将另一个Python脚本称为os.system（“ ./ home / tim / bin / dalitest”）如何在主脚本中杀死另一个Python脚本？

Answer 1

这样的事情应该可以解决问题：

产卵

#spawn by path + return immediately  and get pid
pid = os.spawnl(os.P_NOWAIT, "./home/tim/bin/dalitest")

杀

#kill pid
os.kill(pid, signal.SIGTERM)

#wait for pid to release it back to the system
#this will block until the child is dead
os.waitpid(pid,0)