SQL-如何将列转换为行
[英]SQL - How to convert columns to rows
问题描述
我有以下SQL脚本：
DECLARE @Month AS INT = 5 --Set the MONTH for which you want to generate the Calendar.
DECLARE @Year AS INT = 2015 --Set the YEAR for which you want to generate the Calendar.
DECLARE @StartDate AS DATETIME = CONVERT(VARCHAR,@Year) + RIGHT('0' + CONVERT(VARCHAR,@Month),2) + '01'
DECLARE @EndDate AS DATETIME = DATEADD(DAY,-1,DATEADD(MONTH,1,@StartDate));
SELECT
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 1
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Sunday,
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 2
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Monday,
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 3
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Tuesday,
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 4
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Wednesday,
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 5
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Thursday,
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 6
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Friday,
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 7
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Saturday
FROM master.dbo.spt_values v
WHERE DATEADD(DD,number,@StartDate) BETWEEN @StartDate AND
DATEADD(DAY,-1,DATEADD(MONTH,1,@StartDate)) AND
v.type = 'P'
GROUP BY DATEPART(WEEK, DATEADD(DD,number,@StartDate))
此脚本生成此表：
但是我想得到一个这样的列表：
有什么线索吗？
3 个解决方案
解决方案1
0 2015-05-21 01:56:57
尝试这个：
DECLARE @Month AS INT = 5 --Set the MONTH for which you want to generate the Calendar.
DECLARE @Year AS INT = 2015 --Set the YEAR for which you want to generate the Calendar.
DECLARE @StartDate AS DATETIME = CONVERT(VARCHAR,@Year) + RIGHT('0' + CONVERT(VARCHAR,@Month),2) + '01'
DECLARE @EndDate AS DATETIME = DATEADD(DAY,-1,DATEADD(MONTH,1,@StartDate));
with m1 as (
SELECT
SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 1
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Sunday
,SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 2
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Monday
,SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 3
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Tuesday
,SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 4
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Wednesday
,SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 5
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Thursday
,SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 6
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Friday
,SUM(CASE WHEN DATEPART(DW, DATEADD(DD,number,@StartDate)) = 7
THEN DATEPART(DAY, DATEADD(DD,NUMBER,@StartDate)) END) AS Saturday
FROM master.dbo.spt_values v
WHERE DATEADD(DD,number,@StartDate) BETWEEN @StartDate
AND DATEADD(DAY,-1,DATEADD(MONTH,1,@StartDate))
AND v.type = 'P'
GROUP BY DATEPART(WEEK, DATEADD(DD,number,@StartDate))
)
select
--m.RowNo,
[WeekDay] = d.[WeekDay]
,[Date] = d.[Date]
,[Month] = datename(month,@StartDate)
,[Year] = @Year
from (
select row_number() over (order by Sunday) as RowNo, * from m1
)m
cross apply (values
(0,'Sunday', isnull(cast(Sunday as varchar(2)),' '))
,(1,'Monday', isnull(cast(Monday as varchar(2)),' '))
,(2,'Tuesday', isnull(cast(Tuesday as varchar(2)),' '))
,(3,'Wednesday', isnull(cast(Wednesday as varchar(2)),' '))
,(4,'Thursday', isnull(cast(Thursday as varchar(2)),' '))
,(5,'Friday', isnull(cast(Friday as varchar(2)),' '))
,(6,'Saturday', isnull(cast(Saturday as varchar(2)),' '))
) d(DayNo, [WeekDay], [Date])
order by m.RowNo, d.DayNo
;
产生所需的：
WeekDay Date Month Year
--------- ---- ------------------------------ -----------
Sunday May 2015
Monday May 2015
Tuesday May 2015
Wednesday May 2015
Thursday May 2015
Friday 1 May 2015
Saturday 2 May 2015
Sunday 3 May 2015
Monday 4 May 2015
Tuesday 5 May 2015
Wednesday 6 May 2015
Thursday 7 May 2015
Friday 8 May 2015
Saturday 9 May 2015
Sunday 10 May 2015
Monday 11 May 2015
Tuesday 12 May 2015
Wednesday 13 May 2015
Thursday 14 May 2015
Friday 15 May 2015
Saturday 16 May 2015
Sunday 17 May 2015
Monday 18 May 2015
Tuesday 19 May 2015
Wednesday 20 May 2015
Thursday 21 May 2015
Friday 22 May 2015
Saturday 23 May 2015
Sunday 24 May 2015
Monday 25 May 2015
Tuesday 26 May 2015
Wednesday 27 May 2015
Thursday 28 May 2015
Friday 29 May 2015
Saturday 30 May 2015
Sunday 31 May 2015
Monday May 2015
Tuesday May 2015
Wednesday May 2015
Thursday May 2015
Friday May 2015
Saturday May 2015
解决方案2
0 2015-05-21 02:53:58
这是一个SQL Fiddle，它以您想要的格式生成日期的任意序列。 我将NULL结果的UNION ALL留给读者作为练习。
解决方案3
0 2015-05-21 06:53:39
这是另一个版本：
DECLARE @d DATE = '20150501';
WITH
m AS(SELECT 1 AS d UNION ALL SELECT d+1 FROM m WHERE d < datediff(d, @d, dateadd(m, 1, @d))),
dt AS(SELECT YEAR(@d) y, DATENAME(m, @d) m, d, DATENAME(dw, DATEADD(dd, d-1, @d)) wd FROM m ),
wk AS (SELECT * FROM (VALUES (1, 'Monday'), (2, 'Tuesday'),
(3, 'Wednesday'), (4, 'Thursday'), (5, 'Friday'),
(6, 'Saturday'), (7, 'Sunday')) w(d, n))
SELECT 1 o, y, m, d, wd FROM dt
UNION ALL
SELECT 0, YEAR(@d), DATENAME(m, @d), NULL, w.n FROM wk w
WHERE d < (SELECT d FROM wk WHERE n = (SELECT TOP 1 wd FROM dt ORDER BY d))
UNION ALL
SELECT 2, YEAR(@d), DATENAME(m, @d), NULL, w.n FROM wk w
WHERE d > (SELECT d FROM wk WHERE n = (SELECT TOP 1 wd FROM dt ORDER BY d DESC))
ORDER BY o , d
输出：
o y m d wd
0 2015 May NULL Monday
0 2015 May NULL Tuesday
0 2015 May NULL Wednesday
0 2015 May NULL Thursday
1 2015 May 1 Friday
1 2015 May 2 Saturday
1 2015 May 3 Sunday
1 2015 May 4 Monday
1 2015 May 5 Tuesday
1 2015 May 6 Wednesday
1 2015 May 7 Thursday
1 2015 May 8 Friday
1 2015 May 9 Saturday
1 2015 May 10 Sunday
1 2015 May 11 Monday
1 2015 May 12 Tuesday
1 2015 May 13 Wednesday
1 2015 May 14 Thursday
1 2015 May 15 Friday
1 2015 May 16 Saturday
1 2015 May 17 Sunday
1 2015 May 18 Monday
1 2015 May 19 Tuesday
1 2015 May 20 Wednesday
1 2015 May 21 Thursday
1 2015 May 22 Friday
1 2015 May 23 Saturday
1 2015 May 24 Sunday
1 2015 May 25 Monday
1 2015 May 26 Tuesday
1 2015 May 27 Wednesday
1 2015 May 28 Thursday
1 2015 May 29 Friday
1 2015 May 30 Saturday
1 2015 May 31 Sunday
如何将行转换为列SQL
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.