[英]Oracle SQL 10g query for creating comma separated records
我正在编写用于创建jasper报告的oracle 10g查询。
这是查询-
SELECT essay_id,
LTRIM (
MAX (SYS_CONNECT_BY_PATH (full_name, ','))
KEEP (DENSE_RANK LAST ORDER BY curr),
',')
AS full_name
FROM (SELECT essay_id,
full_name,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY full_name)
AS curr,
ROW_NUMBER ()
OVER (PARTITION BY essay_id ORDER BY full_name)
- 1
AS prev
FROM (SELECT a.id AS essay_id,
CASE NVL (firstname, 'NULL FIRSTNAME')
WHEN 'NULL FIRSTNAME' THEN username
ELSE (firstname || ' ' || lastname)
END
AS full_name
FROM essay_table a
INNER JOIN essay_writer_join ej ON a.id = ej.essay_id
INNER JOIN writer_table u ON ej.user_id = u.id))
GROUP BY essay_id
CONNECT BY prev = PRIOR curr AND essay_id = PRIOR essay_id
START WITH curr = 1
文章是唯一的,但可以有多个作者(essay_writer_join)。此查询为我提供作者的文章,这些作者之间用逗号分隔。
问题是我需要再添加一个称为“ manager”的列,该列将显示作者的管理员。 管理员信息在WRITER_TABLE中,列名称为“ manager_name”。 essay_table具有作者的名字,姓氏和用户名。 棘手的部分是2位作家可以有2位不同的经理。 例如,对于文章“ 123”,作者是“ abc”和“ xyz”,而这些作者的管理者分别是“ lmo”和“ pqr”,那么记录应以以下格式表示
essay id writer manager
123 abc, xyz lmo, pqr
在oracle 10g sql中这可能吗? 我试图搜索类似的情况,但是找不到任何相关的解决方案。
您可以只在最里面的查询和中间的查询中包含manager_name
,然后也对该列重复聚合机制。 我将列和表别名更改为更加一致(并且还简化了case表达式):
SELECT essay_id,
LTRIM (
MAX (SYS_CONNECT_BY_PATH (writer, ','))
KEEP (DENSE_RANK LAST ORDER BY curr),
',')
AS writer,
LTRIM (
MAX (SYS_CONNECT_BY_PATH (manager, ','))
KEEP (DENSE_RANK LAST ORDER BY curr),
',')
AS manager
FROM (SELECT essay_id,
writer,
manager,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY writer)
AS curr,
ROW_NUMBER ()
OVER (PARTITION BY essay_id ORDER BY writer)
- 1
AS prev
FROM (SELECT et.id AS essay_id,
CASE WHEN wt.firstname IS NULL THEN wt.username
ELSE (wt.firstname || ' ' || wt.lastname)
END
AS writer,
wt.manager_name as manager
FROM essay_table et
INNER JOIN essay_writer_join ej ON et.id = ej.essay_id
INNER JOIN writer_table wt ON ej.user_id = wt.id))
GROUP BY essay_id
CONNECT BY prev = PRIOR curr AND essay_id = PRIOR essay_id
START WITH curr = 1;
ESSAY_ID WRITER MANAGER
---------- ---------- ----------
123 abc,xyz lmo,pqr
我能看到的唯一真正的问题是,文章的两位作者是否拥有同一位经理? 那么您将看到重复的值:
ESSAY_ID WRITER MANAGER
---------- ---------- ----------
123 abc,xyz lmo,pqr
456 abc,def lmo,lmo
那可能就是您想要看到的。
如果确实要禁止重复管理器,则可以将聚合分为子查询。 我发现将这些添加到常用表表达式(又称为子查询重构)中时更容易阅读:
WITH all_data AS (
SELECT et.id AS essay_id,
CASE WHEN wt.firstname IS NULL THEN wt.username
ELSE (wt.firstname || ' ' || wt.lastname)
END
AS writer,
wt.manager_name as manager
FROM essay_table et
JOIN essay_writer_join ej ON et.id = ej.essay_id
JOIN writer_table wt ON ej.user_id = wt.id
),
writers AS (
SELECT essay_id,
writer,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY writer) AS rn
FROM (
SELECT distinct essay_id, writer
FROM all_data
)
),
managers AS (
SELECT essay_id,
manager,
ROW_NUMBER () OVER (PARTITION BY essay_id ORDER BY manager) AS rn
FROM (
SELECT distinct essay_id, manager
FROM all_data
)
)
SELECT DISTINCT ad.essay_id,
(
SELECT LTRIM (MAX (SYS_CONNECT_BY_PATH (w.writer, ','))
KEEP (DENSE_RANK LAST ORDER BY w.rn), ',')
FROM writers w
WHERE w.essay_id = ad.essay_id
CONNECT BY w.rn = PRIOR w.rn + 1 AND w.essay_id = PRIOR w.essay_id
START WITH w.rn = 1
) AS writer,
(
SELECT LTRIM (MAX (SYS_CONNECT_BY_PATH (m.manager, ','))
KEEP (DENSE_RANK LAST ORDER BY m.rn), ',')
FROM managers m
WHERE m.essay_id = ad.essay_id
CONNECT BY m.rn = PRIOR m.rn + 1 AND m.essay_id = PRIOR m.essay_id
START WITH m.rn = 1
) AS manager
FROM all_data ad
ORDER BY ad.essay_id;
重要的一点是,分配行号的每个子查询都使用其自己的内联视图来获取不同的值。 因此,对于获得的相同数据:
ESSAY_ID WRITER MANAGER
---------- ---------- ----------
123 abc,xyz lmo,pqr
456 abc,def lmo
SQL小提琴 。
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