Python-如何创建带有参数的新装饰函数？

Question

我读了这篇很棒的文章： 如何制作一系列的函数装饰器？

我决定摆弄它，并从中取走这个方块：

# It’s not black magic, you just have to let the wrapper 
# pass the argument:

def a_decorator_passing_arguments(function_to_decorate):
    def a_wrapper_accepting_arguments(arg1, arg2):
        print "I got args! Look:", arg1, arg2
        function_to_decorate(arg1, arg2)
    return a_wrapper_accepting_arguments

# Since when you are calling the function returned by the decorator, you are
# calling the wrapper, passing arguments to the wrapper will let it pass them to 
# the decorated function

@a_decorator_passing_arguments
def print_full_name(first_name, last_name):
    print "My name is", first_name, last_name

print_full_name("Peter", "Venkman")
# outputs:
#I got args! Look: Peter Venkman
#My name is Peter Venkman

如果我想将修饰的版本另存为其他函数名，例如decorated_print_full_name(first_name, last_name) ，而不是将修饰的print_full_name(first_name, last_name)重命名为本身，该怎么办？ 基本上，我对如何更改代码感到好奇，因此我不使用@a_decorator_passing_arguments快捷方式。

我重写了以上内容（针对Python 3）：

def a_decorator_passing_arguments(function_to_decorate):
    def a_wrapper_accepting_arguments(arg1, arg2):
        print("I got args! Look:", arg1, arg2)
        function_to_decorate(arg1, arg2)
    return a_wrapper_accepting_arguments

#@a_decorator_passing_arguments
def print_full_name(first_name, last_name):
    print("My name is", first_name, last_name)

decorated_print_full_name = a_decorator_passing_arguments(print_full_name(first_name, last_name))

decorated_print_full_name("Peter", "Venkman")

但是Python抱怨在第11行中没有定义first_name 。我还是Python的新手，所以如果我错过这里很明显的内容，请原谅我。

Answer 1

它应与：

decorated_print_full_name = a_decorator_passing_arguments(print_full_name)