在Mac上链接到zeromq的已编译版本时，发出编译Go程序的问题

Question

我已经在Mac OSX 10.9.5上编译了ZeroMQ，以便随后使用github.com/pebbe/zmq4链接到一个简单的Go程序，但是我遇到了这个错误，我不明白或不知道该如何解决。

# github.com/pebbe/zmq4
ld: warning: ignoring file /usr/local/lib/libzmq.dylib, file was built for x86_64 which is not the architecture being linked (i386): /usr/local/lib/libzmq.dylib
Undefined symbols for architecture i386:
  "_zmq_bind", referenced from:
      __cgo_59814aec404b_C2func_zmq_bind in zmq4.cgo2.o
      __cgo_59814aec404b_Cfunc_zmq_bind in zmq4.cgo2.o
     (maybe you meant: __cgo_59814aec404b_Cfunc_zmq_bind, __cgo_59814aec404b_C2func_zmq_bind )
  "_zmq_close", referenced from:
      __cgo_59814aec404b_C2func_zmq_close in zmq4.cgo2.o
      __cgo_59814aec404b_Cfunc_zmq_close in zmq4.cgo2.o
     (maybe you meant: __cgo_59814aec404b_C2func_zmq_close, 
...
  "_zmq_z85_encode", referenced from:
      __cgo_59814aec404b_Cfunc_zmq_z85_encode in zmq4.cgo2.o
     (maybe you meant: __cgo_59814aec404b_Cfunc_zmq_z85_encode)
ld: symbol(s) not found for architecture i386
collect2: error: ld returned 1 exit status

我认为dylib是为x86_64（适用于Mac）制作的，但是Go为什么要尝试与i386链接呢？ 如何控制它并使其链接不同？ 甚至是正确的？

Answer 1

如果您自己构建libzmq，请使用--disable-shared --enable-static密钥进行配置。 如果您使用自制软件，请卸载zmq并手动构建该库。 如果您需要“胖”通用静态库，请使用以下脚本： https : //github.com/drewcrawford/libzmq-ios