搜索和计数字典键值对

Question

如果我有字典

dict = {'brown dogs':3, 'dog of white':4, 'white cats':1, 'white cat':9}

我如何

a）搜索关键子串

b）将所选值相加

所以我得到结果：

('dog', 7) and ('cat', 10)

Answer 1

您可以使用collections.Counter 。

from collections import Counter

d = {'brown dogs':3, 'dog of white':4, 'white cats':1, 'white cat':9}
substrings = ['dog', 'cat']

counter = Counter()

for substring in substrings:
    for key in d:
        if substring in key:
            counter[substring] += d[key]

print(counter.items())

输出：

[('dog', 7), ('cat', 10)]

Answer 2

使用字典来保留字幕：

dict = {'brown dogs':3, 'dog of white':4, 'white cats':1, 'white cat':9}
subs={'dog':0,'cat':0}
for sub in subs.keys():
    for k,v in dict.items():
        if sub in k:
            subs[sub]+=v
print(subs)->{'dog': 7, 'cat': 10}

但是，如果您想自动猜测subs键，则xD可能会更困难！

Answer 3

这是一个替代解决方案：

d = {'brown dogs':3, 'dog of white':4, 'white cats':1, 'white cat':9}
substrings = ['dog', 'cat']
my_list = [(substr, sum([d[key] for key in d.iterkeys() if substr in key])) for substr in substrings]
print my_list

产量

[('dog', 7), ('cat', 10)]

Answer 4

因为需要练习，我会努力解决的！

mydict = {'brown dogs':3, 'dog of white':4, 'white cats':1, 'white cat':9}
mykeys = ['dog', 'cat', 'rhino']
sums_dict = {}
for mkey in mykeys:
    for dkey in mydict.keys():
        if mkey in dkey:
            try:
                sums_dict[mkey] += mydict[dkey]
            except KeyError:
                sums_dict[mkey] = mydict[dkey]
print(sums_dict)