SQL Server中的XML输出

Question

我希望表输出为XML。 我的表结果是

我需要像这样的结果

询问

Declare @colorTable table (Category varchar(100),Attribute varchar(100))
insert into @colorTable values ('Color','Red')
insert into @colorTable values ('Color','Blue')
insert into @colorTable values ('Color','Green')
insert into @colorTable values ('Transport','Bus')
insert into @colorTable values ('Transport','Car')
insert into @colorTable values ('Transport','Twoweeler')

select * from @colorTable
FOR XML PAth(''), ROOT ('xml'), ELEMENTS; 

谢谢，

桑达尔

Answer 1

我们必须使用GROUP BY编写查询，XML路径不允许在xml path(not allowed select statement)内写入sql xml path(not allowed select statement)

Declare @colorTable table (Category varchar(100),Attribute varchar(100))
insert into @colorTable values ('Color','Red')
insert into @colorTable values ('Color','Blue')
insert into @colorTable values ('Color','Green')
insert into @colorTable values ('Transport','Bus')
insert into @colorTable values ('Transport','Car')
insert into @colorTable values ('Transport','Twoweeler')

select T1.Category as '@Value',
       (
       select T2.Attribute as '@Value'
       from @colorTable as T2
       where T2.Category = T1.Category
       group by T2.Attribute
       for xml path('Attribute'), type
       )
from @colorTable as T1
group by Category
for xml path('Category'), root('xml')

输出值

<xml>
  <Category Value="Color">
    <Attribute Value="Blue" />
    <Attribute Value="Green" />
    <Attribute Value="Red" />
  </Category>
  <Category Value="Transport">
    <Attribute Value="Bus" />
    <Attribute Value="Car" />
    <Attribute Value="Twoweeler" />
  </Category>
</xml>

Answer 2

好吧，在特定情况下要实现目标，您应该为三个子支行Color ， Transport和Electronics进行三个子选择，然后将该xml部件加入xml根目录下。

您可以使用以下查询进行操作：

select
    (
        select
            Attribute as 'attribute/@value'
        from @colorTable
        where Category = 'Color'
        for xml path(''), type
    ) as Color,
    (
        select
            Attribute as 'attribute/@value'
        from @colorTable
        where Category = 'Transports'
        for xml path(''), type
    ) as Transports,
    (
        select
            Attribute as 'attribute/@value'
        from @colorTable
        where Category = 'Electronics'
        for xml path(''), type
    ) as Electronics
for xml path(''), root('xml')

Answer 3

看一下EXPLICIT Mode with FOR XML MSDN的 EXPLICIT Mode with FOR XML 。 可能会很痛苦，但是您可以控制输出;-)

Answer 4

最后我把这样的代码

选择Category作为值，（从@colorTable中选择Attribute作为值，其中Category = a.Category
@colorTable中的FOR XML raw（'attribute'），TYPE）按类别分组。FOR XML raw（'category'），ROOT（'xml'），type;