混合和匹配RxJava订阅线程

Question

是否可以在RxJava中混合和匹配调度程序线程。 基本上，我想在Android上执行以下操作。

uiObservable
    .switchMap(o -> return anotherUIObservable)
    .subscribeOn(AndroidSchedulers.mainThread())
    .switchMap(o -> return networkObservable)
    .subscribeOn(Schedulers.newThread())
    .observeOn(AndroidSchedulers.mainThread())
    .subscribe(result -> doSomething(result))

是否可以在同一订阅中进行？

Answer 1

是的，在您完全理解逻辑之后，这是可能的并且非常容易。 但是您可能会混淆observeOn（）和subscribeOn（）运算符：）

uiObservable
    .switchMap(o -> return anotherUIObservable)
    .subscribeOn(AndroidSchedulers.mainThread())  // means that the uiObservable and the switchMap above will run on the mainThread.

    .switchMap(o -> return networkObservable) //this will also run on the main thread

    .subscribeOn(Schedulers.newThread()) // this does nothing as the above subscribeOn will overwrite this

    .observeOn(AndroidSchedulers.mainThread()) // this means that the next operators (here only the subscribe will run on the mainThread
    .subscribe(result -> doSomething(result))

也许这就是您想要的：

uiObservable
    .switchMap(o -> return anotherUIObservable)
    .subscribeOn(AndroidSchedulers.mainThread()) // run the above on the main thread

    .observeOn(Schedulers.newThread())
    .switchMap(o -> return networkObservable) // run this on a new thread

    .observeOn(AndroidSchedulers.mainThread()) // run the subscribe on the mainThread
    .subscribe(result -> doSomething(result))

奖励：我写了一篇有关这些运算符的文章，希望对您有所帮助