总和值乘以记录数

Question

我正在查询表格中上个月的付款总额和帐户对帐单。 我使用以下查询来做到这一点

SELECT DA.ID, DDO.CODE, COALESCE(SUM(FPP.AMOUNT_IN_DEFAULT_CURRENCY),0) AS PAYMENTS,SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY) as STATEMENTS
    FROM DIM_ACCOUNT DA
        JOIN DIM_DATA_OWNER DDO ON DA.DATA_OWNER_ID = DDO.ID
        LEFT JOIN FACT_AS_TRANSACTION FAT ON DA.ID = FAT.ACCOUNT_ID
        JOIN DIM_DATE DD ON FAT.VALUE_DATE_ID = DD.ID
        LEFT JOIN FACT_PAY_PAYMENT FPP ON DA.ID = FPP.ORDERING_ACCOUNT_ID
        JOIN DIM_PAY_PAYMENT_METHOD DPPM ON FPP.PAYMENT_METHOD_ID = DPPM.ID
    WHERE DD.CAL_DATE >= TO_DATE('2015-09-19', 'YYYY-MM-DD')
        AND FPP.CREATION_DATE >= TO_DATE('2015-09-19', 'YYYY-MM-DD')
        AND DPPM.DIRECT_DEBIT_FLAG = 'N' 
        AND FAT.DEBIT_CREDIT_MARK = 'Debit'
    GROUP BY DA.ID, DDO.CODE
    HAVING SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY) != 0;

我加载了3笔付款：

付款A金额2500

付款B金额2500

付款C，金额为2000

付款D，金额为500

我希望总金额为7500。但是，当我执行此查询时，我得到30000。这与7500 * 4相同（我的付款表中有4条记录）。 我想我可能会加入一些错误。 问题是什么？

Answer 1

哪里在打破左边所以它只是加入
或者，如果您将条件加入到联接中，则可以左移
像这样的两个和很少会起作用，因为它们会互相重复
取出分组依据，然后选择值，您将看到所有重复项
FAT中的4行将为您提供FPP中的4行
尝试两次分开，看看是否获得正确答案

SELECT DA.ID, DDO.CODE
     , COALESCE(SUM(FPP.AMOUNT_IN_DEFAULT_CURRENCY),0) AS PAYMENTS
     , SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY)             as STATEMENTS
  FROM DIM_ACCOUNT DA
  JOIN DIM_DATA_OWNER DDO 
        ON DA.DATA_OWNER_ID = DDO.ID
  JOIN FACT_AS_TRANSACTION FAT 
        ON DA.ID = FAT.ACCOUNT_ID
       AND FAT.DEBIT_CREDIT_MARK = 'Debit'
  JOIN DIM_DATE DD 
        ON FAT.VALUE_DATE_ID = DD.ID
       AND DD.CAL_DATE >= TO_DATE('2015-09-19', 'YYYY-MM-DD')
  JOIN FACT_PAY_PAYMENT FPP 
        ON DA.ID = FPP.ORDERING_ACCOUNT_ID 
       AND FPP.CREATION_DATE >= TO_DATE('2015-09-19', 'YYYY-MM-DD')     
  JOIN DIM_PAY_PAYMENT_METHOD DPPM 
        ON FPP.PAYMENT_METHOD_ID = DPPM.ID       
       AND DPPM.DIRECT_DEBIT_FLAG = 'N'              
 GROUP BY DA.ID, DDO.CODE
HAVING SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY) != 0;