使用xpath更新xml文档

Question

您好，这是我的xml文档：

<city> 
  <beirut> 
    <restaurant> 
      <name>sada</name> 
    </restaurant> 
  </beirut>  
  <jbeil> 
    <restaurant> 
      <name>toto</name>  
      <rating>4.3/5</rating> 
    </restaurant>  
    <restaurant> 
      <name>jojo</name>  
      <rating>4.3/5</rating> 
    </restaurant> 
  </jbeil>  
  <sour> 
    <restaurant> 
      <name>sada</name> 
    </restaurant> 
  </sour> 
</city>

我想使用xpath和netbeans将jbeil中“ jojo”餐厅的评分从4.3 / 5更新为4.5 / 5，请帮助，

该代码给出了等级，

  try {
     File inputFile = new File("src/xpath/josephXml.xml");
     DocumentBuilderFactory dbFactory 
        = DocumentBuilderFactory.newInstance();
     DocumentBuilder dBuilder;

     dBuilder = dbFactory.newDocumentBuilder();

     Document doc = dBuilder.parse(inputFile);
     doc.getDocumentElement().normalize();

     XPath xPath =  XPathFactory.newInstance().newXPath();

     String expression = "/City/Jbeil/Restaurant";          
     NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET);
     for (int i = 0; i < nodeList.getLength(); i++) {
        Node nNode = nodeList.item(i);
        System.out.println("\nCurrent Element :" 
           + nNode.getNodeName());
        if (nNode.getNodeType() == Node.ELEMENT_NODE) {
           Element eElement = (Element) nNode;

           System.out.println("rating : " 
              + eElement
                 .getElementsByTagName("rating")
                 .item(0)
                 .getTextContent());

而且我只想更新名称为“ jojo”的jbeil餐厅的评分，请提供帮助

Answer 1

这是一种可能的XPath，它可以在jbeil市中找到名为jojo餐厅，然后返回相应的rating元素：

/city/jbeil/restaurant[name='jojo']/rating

请注意，XML和XPath区分大小写，因此我在上述XPath中使用了所有小写字符来匹配此问题中发布的XML。

我对Java知之甚少，但是通过Internet *快速搜索建议如下：

XPath xpath = XPathFactory.newInstance().newXPath();
String expression = "/city/jbeil/restaurant[name='jojo']/rating"; 
Element e = (Element)xpath.evaluate(expression, doc, XPathConstant.NODE);
if (e != null)
  e.setTextContent("4.5/5");

*） 如何在Java中修改xml标记的特定值？