使用php页面编辑数据库行

Question

我正在尝试生成一个类似页面的电子表格-现在，我从正在显示的数据库中获取了信息，并在另一个页面上允许用户添加信息。

我不明白如何调用数据库以显示设置的行。 我没有运行AI ID，所以这不是问题。 之后，我尝试实施一个，但是这导致我的代码无法正常工作，并给了我空白的页面。

这是我用来显示数据库的代码：

<?php
$link = mysql_connect('', '', ''); 
if (!$link) { 
    die('Could not connect: ' . mysql_error()); 
}

//connect to the database
mysql_select_db(''); 

//query the database
$query = mysql_query("SELECT * FROM ");

        echo "<table border='1'>
            <tr>
            <td class='td'>Date</td>
            <td class='td'>Region</td>
            <td class='td'>Cameraman</td>
            <td class='td'>Livestream?</td>
            <td class='td'>Event Title</td>
            <td class='td'>Lecturer</td>
            <td class='td'>Time</td>
            <td class='td'>Speaker</td>
            <td class='td'>ICE Contact</td>
            <td class='td'>Venue Address</td>
            <td class='td'>Venue Contact</td>
            <td class='td'>Additional Comments</td>
            <td class='td'>On App?</td>
            <td class='td'>Edit</td>
            <td class='td'>Delete</td>
            </tr>";

       WHILE($rows = mysql_fetch_array($query)):
            $rows = array_filter($rows);
            if (!empty($rows)) {
                echo "<tr>";
                echo "<td>" . $rows['date'] . "</td>";
                echo "<td>" . $rows['region'] . "</td>"; 
                echo "<td>" . $rows['cameraman'] . "</td>";
                echo "<td>" . $rows['livestream'] . "</td>"; 
                echo "<td>" . $rows['eventitle'] . "</td>";
                echo "<td>" . $rows['lecturer'] . "</td>"; 
                echo "<td>" . $rows['time'] . "</td>";
                echo "<td>" . $rows['speaker'] . "</td>";
                echo "<td>" . $rows['icecontact'] . "</td>";
                echo "<td>" . $rows['venueaddress'] . "</td>"; 
                echo "<td>" . $rows['venuecontact'] . "</td>";
                echo "<td>" . $rows['additionalcomments'] . "</td>";  
                echo "<td>" . $rows['onapp'] . "</td>";
                echo "<td><a href=""><img src=""></a></td>";
                echo "<td><a href=""><img src=""></a></td>";
                echo "</tr>";
            }
            endwhile;
            echo "</table>";
?>

任何帮助，将不胜感激。 谢谢

Answer 1

如果在if块的第三行和倒数第二行中存在引号不匹配的情况，则在双引号中使用双引号会导致语法错误。 在此，将外部双引号替换为单引号。 像这样更新if块：

if (!empty($rows)) {
                echo "<tr>";
                echo "<td>" . $rows['date'] . "</td>";
                echo "<td>" . $rows['region'] . "</td>"; 
                echo "<td>" . $rows['cameraman'] . "</td>";
                echo "<td>" . $rows['livestream'] . "</td>"; 
                echo "<td>" . $rows['eventitle'] . "</td>";
                echo "<td>" . $rows['lecturer'] . "</td>"; 
                echo "<td>" . $rows['time'] . "</td>";
                echo "<td>" . $rows['speaker'] . "</td>";
                echo "<td>" . $rows['icecontact'] . "</td>";
                echo "<td>" . $rows['venueaddress'] . "</td>"; 
                echo "<td>" . $rows['venuecontact'] . "</td>";
                echo "<td>" . $rows['additionalcomments'] . "</td>";  
                echo "<td>" . $rows['onapp'] . "</td>";
                echo '<td><a href=""><img src=""></a></td>';
                echo '<td><a href=""><img src=""></a></td>';
                echo "</tr>";
            }