保存时使用openpyxl从一个工作簿复制到另一个工作簿会导致错误

Question

我试图将一个工作表中的值逐行追加到新工作簿中。 当我在一个小的测试文件上运行它时，我的代码可以工作，但是当我在目标文件上运行它时，它在保存时返回错误。

这是我的代码：

from openpyxl import load_workbook
from openpyxl import Workbook

wb = load_workbook(filename='RM Activity-Pricing Report - 2014-05-31.xlsm',keep_vba=False, data_only=True)
ws_Ottawa = wb.get_sheet_by_name('Ottawa')

wb2 = Workbook()
ws2 = wb2.create_sheet()

for row in ws_Ottawa.iter_rows():
        ws2.append(row)

wb2.save('new_big_file.xlsx')

我在Spyder（python 3.5）中得到的输出错误是：

Traceback (most recent call last):

File "<ipython-input-22-171ffbcd4891>", line 1, in <module>
runfile('Z:/Revenue Management Report/ExtractPromoData.py', wdir='Z:/Revenue Management Report')

File "C:\Anaconda3-64\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 699, in runfile
execfile(filename, namespace)

File "C:\Anaconda3-64\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 88, in execfile
exec(compile(open(filename, 'rb').read(), filename, 'exec'), namespace)

File "Z:/Revenue Management Report/ExtractPromoData.py", line 35, in <module>
wb2.save('new_big_file4.xlsx')

File "C:\Anaconda3-64\lib\site-packages\openpyxl\workbook\workbook.py", line 298, in save
save_workbook(self, filename)

File "C:\Anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 198, in save_workbook
writer.save(filename, as_template=as_template)

File "C:\Anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 181, in save
self.write_data(archive, as_template=as_template)

File "C:\Anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 87, in write_data
self._write_worksheets(archive)

File "C:\Anaconda3-64\lib\site-packages\openpyxl\writer\excel.py", line 114, in _write_worksheets
write_worksheet(sheet, self.workbook.shared_strings,

File "C:\Anaconda3-64\lib\site-packages\openpyxl\writer\worksheet.py", line 233, in write_worksheet
write_rows(xf, worksheet)

File "C:\Anaconda3-64\lib\site-packages\openpyxl\writer\lxml_worksheet.py", line 59, in write_rows
if cell.value is None and not cell.has_style:

File "C:\Anaconda3-64\lib\site-packages\openpyxl\cell\cell.py", line 306, in value
if value is not None and self.is_date:

File "C:\Anaconda3-64\lib\site-packages\openpyxl\cell\cell.py", line 351, in is_date
if self.data_type == "n" and self.number_format != "General":

File "C:\Anaconda3-64\lib\site-packages\openpyxl\styles\styleable.py", line 49, in __get__
return coll[idx - 164]
IndexError: list index out of range

在较小的测试.xlsx文件上使用代码时，没有出现错误。

我怀疑该问题的可能原因是：

1）输入文件是.xlsm

2）输入文件的列从A到CI

3）输入文件受密码保护（但是由于保存时出错，这似乎不应该成为问题）

考虑到查理说的话，这是我从openpyxl import Workbook到openpyxl import load_workbook的解决方法

 wb = load_workbook(filename='RM Activity-Pricing Report - 2014-5-31.xlsm',keep_vba=False, data_only=True)#,guess_types=True)


ws_Ottawa = wb.get_sheet_by_name('Ottawa')

wb2 = Workbook()
ws2 = wb2.create_sheet()
counter = 0
new_rows = []
for rrow in ws_Ottawa.iter_rows():
    new_rows.append([])
    for cell in rrow:
        new_rows[counter].append(cell.value)
    counter +=1
for wrow in new_rows:

    ws2.append(wrow)

wb2.save('new_big_file4.xlsx')


print("ALL DONE")

Answer 1

您完全无法做您想做的事情。 不幸的是，数据在文件格式中的存储方式意味着许多相关信息没有随单元存储，而是使用对工作簿对象的引用。 这些显然在工作簿之间是不同的，这就是为什么保存时会看到错误：新文件中不存在您要使用的数字格式。