如何正确计算json内容？

Question

这是我的json

[
    {"id":"1736375","first_name":"fname1","force_first_name":"ffname1","last_name":"lname1","thumb_path":"","path":"img\/profiles\/generic\/gray.png"},
    {"id":"1607011","first_name":"fname2","force_first_name":"ffname2","last_name":"lname2","thumb_path":"","path":"img\/profiles\/generic\/gray.png"},
    {"id":"1607012","first_name":"fname3","force_first_name":"ffname3","last_name":"lname3","thumb_path":"","path":"img\/profiles\/generic\/gray.png"}
]

我正在尝试计算[]中的套数

我尝试使用这个

echo count(json_decode($people, true));

我得到零（0）结果。

我该如何正确地计算它。

谢谢

===为将来的观看者编辑===

它是json格式不正确，如几条评论所述，我在上面编写的代码是我的看到方式，但json的真正内容是

string(3)"
[
    {"id":"1736375","first_name":"fname1","force_first_name":"ffname1","last_name":"lname1","thumb_path":"","path":"img\/profiles\/generic\/gray.png"},
    {"id":"1607011","first_name":"fname2","force_first_name":"ffname2","last_name":"lname2","thumb_path":"","path":"img\/profiles\/generic\/gray.png"},
    {"id":"1607012","first_name":"fname3","force_first_name":"ffname3","last_name":"lname3","thumb_path":"","path":"img\/profiles\/generic\/gray.png"}
]"

如@dontpanic所指出的，字符串将始终返回1，这就是我得到的。 我向开发人员报告了该问题，幸运的是，他们更正了json响应，现在它可以正常工作了。

感谢所有努力发表评论以发现问题的人。

Answer 1

使用此确切的代码，我得到所需的输出3 ，以及上面的其他注释。 我建议调试$people变量，以确保它一直是json对象，直到您的echo语句为止，因为很有可能它要么格式错误，要么一起更改，因此给您带来意想不到的结果。

<?php
$people = <<<EOD
[
    {"id":"1736375","first_name":"fname1","force_first_name":"ffname1","last_name":"lname1","thumb_path":"","path":"img\/profiles\/generic\/gray.png"},
    {"id":"1607011","first_name":"fname2","force_first_name":"ffname2","last_name":"lname2","thumb_path":"","path":"img\/profiles\/generic\/gray.png"},
    {"id":"1607012","first_name":"fname3","force_first_name":"ffname3","last_name":"lname3","thumb_path":"","path":"img\/profiles\/generic\/gray.png"}
]
EOD;

echo count(json_decode($people, true));

Answer 2

尝试：

echo count(json_decode(stripslashes($people), true));