扫雷器中的Python逻辑

Question

我目前正在写扫雷游戏。 一切正常，直到我一次单击即可暴露多个图块的问题。 每当我单击某个东西时，它都不会显示地雷（应该是这样），而只会向下，向左和向右滑动。 我做到了，所以它打印了方向，并且认为向下是正确的，依此类推。我从未遇到过左边。 这是我的代码：

from tkinter import *
from random import *

root = Tk()
root.resizable(0, 0)
root.title("Minesweeper")
frame = Frame(root)

Grid.rowconfigure(root, 0, weight=1)
Grid.columnconfigure(root, 0, weight=1)
frame.grid(row=0, column=0)

class Tiles:
    def __init__(self, frame, size, minecount):
        self.size = size
        self.frame = frame
        self.tiles = []
        self.minearray = []
        self.curmines = 0
        self.minecount = minecount

        for x in range(self.size):
            self.tiles.append([])
            self.minearray.append([])
            for y in range(self.size):
                self.minearray[x].append(0)
                self.tiles[x].append(Button())
                self.tiles[x][y] = Button(self.frame, text=' ', width=2, bd = 3, bg="#CDCDCD", command=lambda row=x, col=y: self.clicked(row, col))
                self.tiles[x][y].grid(row=x, column=y)

        self.setMines()

    def setMines(self):
        for i in range(self.minecount):
            self.minearray[randint(0, self.size - 1)][randint(0, self.size - 1)] = 1
            self.curmines += 1
        print(self.minearray)

    def clicked(self, x, y):
        if self.minearray[x][y] == 1:
            self.tiles[x][y]["text"] = '@'
        self.tiles[x][y]["relief"] = SUNKEN
        self.minearray[x][y] = 2
        if x < self.size - 1 and self.minearray[x+1][y] == 0:
            self.clicked(x+1, y)
            print('r')
            if y > 0 and self.minearray[x+1][y-1] == 0:
                self.clicked(x+1, y-1)
                print('rd')
            if y < self.size - 1 and self.minearray[x+1][y+1] == 0:
                self.clicked(x+1, y+1)
                print('ru')

        if x > 0 and self.tiles[x-1][y] == 0:
            self.clicked(x-1, y)
            print('l')
            if y > 0 and self.minearray[x-1][y-1] == 0:
                self.clicked(x-1, y-1)
                print('ld')
            if y < self.size - 1 and self.minearray[x-1][y+1] == 0:
                self.clicked(x-1, y+1)
                print('lu')

        if y < self.size - 1 and self.tiles[x][y + 1] == 0:
            self.clicked(x, y + 1)
            print('u')

        if y > 0 and self.tiles[x][y - 1] == 0:
            self.clicked(x, y - 1)
            print('d')

tiles = Tiles(frame, 10, 20)

root.mainloop()

逻辑在单击的函数中：

def clicked(self, x, y):
    if self.minearray[x][u] == 1:
        self.tiles[x][y]["text"] = '@'
    self.tiles[x][y]["relief"] = SUNKEN
    self.minearray[x][y] = 2
    if x < self.size - 1 and self.minearray[x+1][y] == 0:
        self.clicked(x+1, y)
        print('r')
        if y > 0 and self.minearray[x+1][y-1] == 0:
            self.clicked(x+1, y-1)
            print('rd')
        if y < self.size - 1 and self.minearray[x+1][y+1] == 0:
            self.clicked(x+1, y+1)
            print('ru')

    if x > 0 and self.tiles[x-1][y] == 0:
        self.clicked(x-1, y)
        print('l')
        if y > 0 and self.minearray[x-1][y-1] == 0:
            self.clicked(x-1, y-1)
            print('ld')
        if y < self.size - 1 and self.minearray[x-1][y+1] == 0:
            self.clicked(x-1, y+1)
            print('lu')

    if y < self.size - 1 and self.tiles[x][y + 1] == 0:
        self.clicked(x, y + 1)
        print('u')

    if y > 0 and self.tiles[x][y - 1] == 0:
        self.clicked(x, y - 1)
        print('d')

Answer 1

您似乎前后矛盾。 在某些条款中，您检查self.minearray ，而在其他条款中，您检查self.tiles 。 从初始化代码来看，它确实应该是self.minearray ，因为self.tiles[anything][anything]永远不会是== 0 。