PHP-Foreach对象

Question

我试图在我的视图中遍历此数据对象。 但是，出现以下错误： Trying to get property of non-object 。 这是我第一次真正遇到渲染数组/对象的问题...也许只是星期日的情况...但是我无法将此foreach输出。 救命？ 编辑：我将键/值“ search_type”添加到返回的数组中-我认为这可能是导致问题的原因？

$results = $twitter->get("users/search", ["q" => $term, "count" => $num, "include_entities" => 'false']);
$results['search_type'] = 'people';

返回：

{
    "0": {
        "id": 1108217089,
        "id_str": "1108217089",
        "name": "Marketing",
        "screen_name": "SocialMedia246",
        "location": "Canada",
        "description": "Marketing|PR|Brand Consultant.Lover of Music|Fashion & life.A dynamic young entrepreneur with an unconventional out of the box approach to marketing & business.",
    },
    "1": {
        ...
    },
    search_type: "people"

Foreach：

@foreach ($search_results as $result => $profile)
    <div class="large-3 columns">               
        {{ $profile->id }}
    </div>
@endforeach

最小化的vardump，用于search_results：

array:21 [▼
  0 => {#433 ▶}
  1 => {#435 ▶}
  2 => {#449 ▶}
  3 => {#455 ▶}
  4 => {#461 ▶}
  5 => {#468 ▶}
  6 => {#472 ▶}
  7 => {#479 ▶}
  8 => {#492 ▶}
  9 => {#505 ▶}
  10 => {#513 ▶}
  11 => {#526 ▶}
  12 => {#531 ▶}
  13 => {#538 ▶}
  14 => {#542 ▶}
  15 => {#548 ▶}
  16 => {#555 ▶}
  17 => {#560 ▶}
  18 => {#564 ▶}
  19 => {#577 ▶}
  "search_type" => "people"
]

Answer 1

我相信您没有正确读取文件。

请尝试以下循环：

<?php
    $sInFile  = 'in3.json';
    $sOutFile = 'out3.json';

    $sRaw     = file_get_contents( $sInFile );
    $aData    = json_decode( $sRaw, 1 );

    // $aData = array();
    // $aTmp                  = array();
    // $aTmp[ 'id' ]          = '1108217089';
    // $aTmp[ 'id_str' ]      = '1108217089';
    // $aTmp[ 'name' ]        = 'Marketing';
    // $aTmp[ 'screen_name' ] = 'SocialMedia246';
    // $aTmp[ 'location' ]    = 'Canada';
    // $aTmp[ 'description' ] = 'Marketing';
    // $aData[] = ( object ) $aTmp;

    // $aTmp                  = array();
    // $aTmp[ 'id' ]          = '1108217089';
    // $aTmp[ 'id_str' ]      = '1108217089';
    // $aTmp[ 'name' ]        = 'Marketing';
    // $aTmp[ 'screen_name' ] = 'SocialMedia246';
    // $aTmp[ 'location' ]    = 'Canada';
    // $aTmp[ 'description' ] = 'Marketing';
    // $aData[] = ( object ) $aTmp;


    foreach ($aData as $result => $profile)
    {
        var_dump( $result );
        var_dump( $profile );
        var_dump( $profile->id );
    }
    var_dump( $aData );

    $sNewJson = json_encode( $aData );
    var_dump( $sNewJson );
    file_put_contents( $sOutFile, $sNewJson );

?>

Answer 2

您的问题是，您正在尝试从string people获取id属性。

Answer 3

好的，@ potfur在他的评论中提到了一个很好的观点。 与其添加键search_type ， search_type将其保存到这样的people数组中。 救救我麻烦和头痛。 谢谢你们的帮助。 我本该接受这个错误。

$results['people'] = $twitter->get("users/search", ["q" => $term, "count" => $num, "include_entities" => 'false']);

vardump现在是（这更有意义）：

array:1 [▼
  "people" => array:20 [▶]
]