猜数字游戏python

Question

所以我正在做一个猜测数字游戏，要求之一是要更新数字的“范围”，以便用户可以更轻松地进行猜测。 当数字太高或太低时，我都创建了一个新输入。 但是，我对循环不是很好，而且我无法弄清楚为什么我的循环只重复一次而没有一遍又一遍地粘贴代码。 任何人都可以帮忙，以便elif语句会重复直到数字正确为止？

到目前为止，这是我的代码...

import random
random_number = random.randint(1,100)
tries = 0
while tries < 800:
  guess = input("Guess a random number between 1 and 100.")       
  tries += 1
  try:
    guess_num = int(guess)
  except:
    print("That's not a whole number!")
    break

  if not guess_num > 0 or not guess_num < 101:
    print("That number is not between 1 and 100.")
    break

  elif guess_num == random_number:
    print("Congratulations! You are correct!")
    print("It took you {} tries.".format(tries))
    break

  elif guess_num > random_number:
      print("Sorry that number is too high.")
      guess_high = input("Guess a number between 0 and {} .".format(guess_num))

  elif guess_num < random_number:
      print("Sorry that number is too low.")
      guess_low = input("Guess a number between {} and 100 .".format(guess_num))

  else:
      print("Sorry, but my number was {}".format(random_number))
      print("You are out of tries. Better luck next time.")

Answer 1

import random
random_number = random.randint(1,100)
tries = 0
guess = input("Guess a random number between 1 and 100.")       
while tries < 800:
  tries += 1
  try:
    guess_num = int(guess)
  except:
    print("That's not a whole number!")
    break

  if not guess_num > 0 or not guess_num < 101:
    print("That number is not between 1 and 100.")
    break

  elif guess_num == random_number:
    print("Congratulations! You are correct!")
    print("It took you {} tries.".format(tries))
    break

  elif guess_num > random_number:
      print("Sorry that number is too high.")
      guess = input("Guess a number between 0 and {} .".format(guess_num))

  elif guess_num < random_number:
      print("Sorry that number is too low.")
      guess = input("Guess a number between {} and 100 .".format(guess_num))

else:
  print("Sorry, but my number was {}".format(random_number))
  print("You are out of tries. Better luck next time.")

Answer 2

在哪种情况下，您的循环仅重复一次？

如果输入的猜测值小​​于0或大于100，则循环将中断（因为在第15行的“ if notgues_num> 0或notgues_num <101：”下有一个break语句）。

如果用户输入的错误猜测在1到100之间，则代码会循环，因此要求用户输入另一个数字。

尽管确实循环，但该循环不会更新范围。 您可以做的是将range_min和range_max设置为变量，并根据猜测值太低还是太高来更改这些变量。 请参见以下代码：

import random
random_number = random.randint(1,100)
tries = 0
range_min = 0
range_max = 100
while tries < 800:
  guess = input("Guess a random number between " + str(range_min +1) + " and " +  str(range_max))       
  tries += 1
  try:
    guess_num = int(guess)
  except:
    print("That's not a whole number!")
    break

  if not guess_num > range_min or not guess_num < (range_max+1):
    print("That number is not between str(range_min +1) + " and " +      str(range_max)")
    break

  elif guess_num == random_number:
    print("Congratulations! You are correct!")
    print("It took you {} tries.".format(tries))
    break

  elif guess_num > random_number:
      print("Sorry that number is too high.")
      guess_high = input("Guess a number between 0 and {} .".format(guess_num))
range_max = guess_num

  elif guess_num < random_number:
      print("Sorry that number is too low.")
      guess_low = input("Guess a number between {} and 100 .".format(guess_num))
range_min = guess_num

  else:
      print("Sorry, but my number was {}".format(random_number))
          print("You are out of tries. Better luck next time.") 

Answer 3

1. 不要使用break ，因为它们会终止while循环。 请参阅python语言参考。

2. 您只需要询问一次guess_num 。 当猜测值太高或太低（BTW变量名称guess不正确）时，请删除两个input 。

3. 最后一个条件（尝试次数除外）应在while循环之外，因为它将在尝试次数超过800次时执行。

4. 暗示。 用户可以进行与二分搜索相当的游戏（从50开始，然后猜测25或75，具体取决于更高/更低，等等）。 您应该允许大约8次尝试（而不是800次）。

Answer 4

以下是更新范围的方法：

import random
random_number = random.randint(1,100)
tries = 0
low = 0
high = 100
while tries < 800:
  if(tries == 0):
    guess = input("Guess a random number between {} and {}.".format(low, high))       
  tries += 1
  try:
    guess_num = int(guess)
  except:
    print("That's not a whole number!")
    break    

  if guess_num < low or guess_num > high:
    print("That number is not between {} and {}.".format(low, high))
    break    

  elif guess_num == random_number:
    print("Congratulations! You are correct!")
    print("It took you {} tries.".format(tries))
    break    

  elif guess_num > random_number:
      print("Sorry that number is too high.")
      high = guess_num
      guess = input("Guess a number between {} and {} .".format(low, high))    

  elif guess_num < random_number:
      print("Sorry that number is too low.")
      low = guess_num
      guess = input("Guess a number between {} and {} .".format(low, high))    

  else:
      print("Sorry, but my number was {}".format(random_number))
      print("You are out of tries. Better luck next time.")

Answer 5

这就是我要怎么做。 不知道它是否有效，但是方法是：

import random

random_number = random.randint(1,100)
max_tries = 100 
tries = 0
left = 0
right = 100
found = False


def get_number():
    try:
        guess = int(input("Guss a random number between {} and {}".format(left, right)))            
        if guess > right or guess < left:
            print("That number is not between {} and {}".format(left, right))
        return guess
    except:
        print("That's not a whole number!")
        get_number()

def update_range(guess):
    if guess >= left:
        left = guess
    else:
        right = guess        

while tries <= max_tries and not found:
    guess = get_number()
    tries=+1
    if guess == random_number:
        print("Congratulations! You are correct!")
        print("It took you {} tries.".format(tries))
        found = True
    else:
        update_range(guess)

  if not found:
      print("Sorry, but my number was {}".format(random_number))
      print("You are out of tries. Better luck next time.")

如您所见，我正在使用辅助函数以减少if / else结构的数量。

此外，还需要更新范围 。 并且由于参数化的字符串，我可以告诉用户范围是多少。

我还设置了一个标志来了解用户是否在游戏结束时找到了号码