从文本文件中查找平均值

Question

我正在尝试查找文本文件中每一行同一行数字的平均值。 例如，如果这是文本文件：

8.7 6.5 0.1 3.2 5.7 9.9 8.3 6.5 6.5 1.5
0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0.0
1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0

我想打印类似：

For Competitor #1, the average is 5.8625
For Competitor #2, the average is 0.0000
For Competitor #3, the average is 1.0000

这是我的代码。

import java.io.*;
import java.util.*;
import java.text.*;
public class BaseClass
{
    public static void main(String args[]) throws IOException
{
    NumberFormat fmt = NumberFormat.getNumberInstance();
    fmt.setMinimumFractionDigits(4);
    fmt.setMaximumFractionDigits(4);
    Scanner sf = new Scanner(new File("C:\\temp_Name\\DataGym.in.txt"));
    int maxIndx = -1;
    String text[] = new String[1000];

    while (sf.hasNext()) {
        maxIndx++;
        text[maxIndx] = sf.nextLine();
    }
    sf.close();
    int contestant = 0;

    for (int j = 0; j <= maxIndx; j++) {
        Scanner sc = new Scanner(text[j]);
        double scoreAverage = 0;
        double a = 0;
        double array[] = new double[1000];
        contestant++;
        if (j <= 10) {
            a += sc.nextDouble();
            array[j] += a;
        } else {
            Arrays.sort(array);
            int i = 0;
            while (i < 10) {
                scoreAverage += array[i];
                i++;
            }
        }

            String s = fmt.format(scoreAverage);
            double d = Double.parseDouble(s);
         System.out.println("For Competitor #" + contestant + ", the average is " + d);
    }
    }
}

它打印

For the Competitor #1, the average is 0.0
For the Competitor #2, the average is 0.0
For the Competitor #3, the average is 0.0

Answer 1

您在这里使问题复杂化了。 遵循以下摘录足以使您实现此处想要达到的目标。

这是代码片段：

public static void main (String[] args) throws Exception
{
    Scanner in = new Scanner(new File("C:\\temp_Name\\DataGym.in.txt"));
    int counter = 0;
    String line = null;
    while(in.hasNext()) {
        line = in.nextLine();
        double sum = 0;
        String[] splits = line.split(" ");
        for(String s : splits) {
            sum += Double.parseDouble(s);
        }
        System.out.println("For Competitor #" + (++counter) 
                           + ", the average is " + (sum/splits.length));
    }
}

输出：

For Competitor #1, the average is 5.69
For Competitor #2, the average is 0.0
For Competitor #3, the average is 1.0