如何从while循环内的while循环中获取数据

Question

我有这个代码和事情它是一个奇怪的但当我从第一个查询得到last_name是一个唯一的数字，并借助于我得到另一个表的姓氏的拼写，但当我尝试获取另一个数据时低于第二个结束它认为第一个while循环已经结束，然后我无法从第一个while循环中获取剩余的数据，我甚至尝试了这个代码但不幸的是它对我不起作用

<div class="row">
    <?php 
    $sql2 = "SELECT id,last_name,age,height,weight,gender,education,work
             from profile where parent_key!='$parent_key' ";
    $retval2 = mysqli_query($con,$sql2);

    if(! $retval2 ) {
        die('Could not get data: ' . mysql_error());
    }

    while($row = mysqli_fetch_array($retval2, MYSQL_ASSOC)) {
    ?>

    <div class="row">
        <div class="col-lg-6 col-md-6 col-sm-6">
            <span>Unique Id</span>
            <h3><?php  echo $row['id'] ?></h3>
        </div>
    <div class="col-lg-6 col-md-6 col-sm-6">
        <span>Surname</span>
        <h3><?php $surname = $row['last_name']; 
            $sql3 = "SELECT last_name from surname where id='$surname'";
            $retval3 = mysqli_query($con,$sql3);
            if(! $retval3 ) {
                die('Could not get data: ' . mysql_error());
            }
            while($row = mysqli_fetch_array($retval3, MYSQL_ASSOC)) {
                echo $new_last_name ="{$row['last_name']}";
            ?>
            ?>
        </h3>
    </div>

</div>
<!-- /.row -->


<!-- /.row -->

<?php
    }
?>

<?php
    }
?>
</div>
<!-- /.row -->

并感谢您提前帮助。

Answer 1

您可以使用单个查询从其他表中获取用户名和姓（姓）

     $sql2 = "SELECT surname.last_name as surname,profile.id as id,profile.last_name,profile.age,profile.height,profile.weight,profile.gender,profile.education,profile.work
                     from profile 
left join surname on surname.id=profile.last_name
    where parent_key!='$parent_key' ";

现在您不需要两次编写代码来获取姓氏

完整代码如下

<div class="row">
                <?p$sql2 = "SELECT surname.last_name as surname,profile.id as id,
                                profile.last_name,profile.age,profile.height,profile.weight,profile.gender,profile.education,
                                profile.work
                         from profile 
                            left join surname on surname.id=profile.last_name
                            where parent_key!='$parent_key' ";
                    $retval2 = mysqli_query($con,$sql2);

                    if(! $retval2 ) 
                    {
                        die('Could not get data: ' . mysql_error());
                    }



                    while($row = mysqli_fetch_array($retval2, MYSQL_ASSOC)) 
                    {
                        ?>

                        <div class="row">
                            <div class="col-lg-6 col-md-6 col-sm-6">
                                <span>Unique Id</span>
                                <h3><?php  echo $row['id'] ?></h3>
                            </div>
                            <div class="col-lg-6 col-md-6 col-sm-6">
                                <span>Surname</span>
                                <h3><?php echo $row['surname'];       ?>                                 

                                </h3>
                            </div>

                        </div>


                    <?php
                        }
                    ?>
           </div>

Answer 2

在第二个while循环内部改变：

$row = mysqli_fetch_array($retval3, MYSQL_ASSOC)

至

$row1 = mysqli_fetch_array($retval3, MYSQL_ASSOC)

那么你可以使用$row['columnname'] first $row['columnname']第一个值和第二个$row1['columnname']