PHP-将CSV文件流式传输到浏览器

Question

我在将CSV文件直接下载到浏览器而不将文件存储在服务器上的位置时遇到问题。 我找到了一个教程（ https://www.perpetual-beta.org/weblog/php-stream-file-direct.html ），但我似乎无法使其正常运行！

这是我的主要功能：

public function exportRecord($id) {
    $contest = (string) $this->getContest($id);
    $entries = (array) $this->getEntries($id);

    $filename = sprintf('%1$s-%2$s-%3$s', str_replace(' ', '', $contest['name']), date('Ymd'), date('His'));
    $output = fopen('php://output', 'w');

    ob_start();

    $header = array(
        'First Name',
        'Last Name',
        'Address',
        'City',
        'State',
        'Zip',
        'Phone',
        'Email',
        'Item Purchased',
        'Partner Name',
        'Partner #',
        'Date Entered',
        'Subscribe'
    );

    fputcsv($output, $header);

    foreach ($entries as $entry) {
        fputcsv($output, $entry);
    }

    $string = ob_get_clean();

    header('Pragma: public');
    header('Expires: 0');
    header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
    header('Cache-Control: private', false);
    header('Content-Type: application/octet-stream');
    header('Content-Disposition: attachment; filename="' . $filename . '.csv";');
    header('Content-Transfer-Encoding: binary');

    exit($string);
}

我正在调用以下两个函数，它们仅对数据库进行查询...

private function getContest($id) {
    $query = sprintf(
        'SELECT name ' .
        'FROM contests ' .
        'WHERE id = %s;',
        $id
    );

    $result = $this->mysql->query($query);
    $response = '';

    if ($result) {
        while ($row = mysqli_fetch_assoc($result)) {
            $response = $row;
        }
    } else {
        echo $this->mysql->error;
    }

    return $response;
}

private function getEntries($id) {
    $query = sprintf(
        'SELECT firstName, ' .
            'lastName, ' .
            'CONCAT(address1, ", ", address2), ' .
            'city, ' .
            'state, ' .
            'zip, ' .
            'phone, ' .
            'email, ' .
            'itemPurchased, ' .
            'partnerName, ' .
            'partnerNum, ' .
            'dateEntered, ' .
            'subscribe ' .
        'FROM entries ' .
        'WHERE contestID = %s;',
        $id
    );

    $result = $this->mysql->query($query);
    $response = '';

    if ($result) {
        while ($row = mysqli_fetch_assoc($result)) {
            $response[] = $row;
        }
    } else {
        echo $this->mysql->error;
    }

    return $response;
}

感谢您提供的任何帮助/建议！ 以下是屏幕截图，目的是让您大致了解问题所在： 谢谢！

Answer 1

乔纳森·霍林（Jonathan Hollin）的样本中缺少几个步骤。 您需要开始输出缓冲，必须将缓冲区写出并正确设置标头。 这可能需要进行一些修改，但是我尝试使该示例适应您在此问题中提供的内容：

<?php
public function exportRecord($id) {
    $contest = (array) $this->getContest($id);
    $entries = (array) $this->getEntries($id);

    $filename = sprintf('%1$s-%2$s-%3$s', str_replace(' ', '', $contest['name']), date('Ymd'), date('His'));

    $header = array(
        'First Name',
        'Last Name',
        'Address',
        'City',
        'State',
        'Zip',
        'Phone',
        'Email',
        'Item Purchased',
        'Partner Name',
        'Partner #',
        'Date Entered',
        'Subscribe'
    );

    export_csv($header, $entries, $filename);
}

private function export_csv($header, $data, $filename) {
    // No point in creating the export file on the file-system. We'll stream
    // it straight to the browser. Much nicer.

    // Open the output stream
    $fh = fopen('php://output', 'w');

    // Start output buffering (to capture stream contents)
    ob_start();

    // CSV Header
    if(is_array($header)){
        fputcsv($fh, $header);
    }

    // CSV Data
    foreach ($data as $row) {
        fputcsv($fh, $row);
    }

    // Get the contents of the output buffer
    $string = ob_get_clean();

    // Output CSV-specific headers
    header('Pragma: public');
    header('Expires: 0');
    header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
    header('Cache-Control: private', false);
    header('Content-Type: application/octet-stream');
    header('Content-Disposition: attachment; filename="' . $filename . '.csv";');
    header('Content-Transfer-Encoding: binary');

    // Stream the CSV data
    exit($string);
}

Answer 2

我最终用JS完成了此操作。

                    } else if (action == 'export') {
                    if (result.data !== false) {
                        var data = encodeURIComponent(result.data);
                        var contest = result.contest.trim();
                        var filename = contest + '.csv';
                        var dataUri = 'data:text/csv;charset=utf-8,' + data;
                        var link = document.createElement('a');

                        link.setAttribute('href', dataUri);
                        link.setAttribute('download', filename);
                        document.body.appendChild(link);
                        link.click();

                        showMessage('Export successfully created!', 'success');
                    } else {
                        showMessage('There are no entries for this contest! Nothing to export...', 'error');
                    }
                }