多行到单行，多列，最小日期

Question

我有一张看起来像下面的桌子，我想做两件事。 1号 选择Min（EnterDtm）记录，在这种情况下，将为2015-08-25 05：29：44：480。 我还希望有一个记录行，该行具有身高英尺，身高英寸和体重kg作为新列名，而每个新列的下面是ObsText

EnterDtm                 ObsCatalogName    VisitID  OBSTEXT
2015-08-25 05:29:44.480 AS height feet NU   219975  5
2015-08-25 05:29:44.480 AS height inches NU 219975  5
2015-08-25 05:29:44.480 AS weight kg CAL    219975  88
2015-08-25 07:05:11.173 AS weight kg CAL    219975  90.6
2015-08-26 06:36:43.537 AS weight kg CAL    219975  90.5
2015-08-26 21:22:21.550 AS height feet NU   219975  5
2015-08-26 21:22:21.550 AS height inches NU 219975  6
2015-08-26 21:22:21.550 AS weight kg CAL    219975  90.5
2015-08-27 05:55:27.373 AS weight kg CAL    219975  87.4

我希望它看起来像这样

 EnterDtm                  VisitID  Height Feet  Height Inches  Weight
 2015-08-25 05:29:44.480    219975  5             5               88

Answer 1

首先，我With cte （您可以很容易地使用内联视图）在通用表表达式中生成一组数据，其中包含使用case语句所需格式的字段。

这还会通过使用基于日期和访问的amx将字段组合到一个记录中，并为按日期排序的访问分配等级。

然后，我从CTE中生成的数据集中选择所有记录，其中每个visitID的排名为1（最低的enterDTM）

未测试：

With CTE AS (
Select EnterDTM
,OVisitID
,max(case when OBSCatalogName = 'height feet NU' then OBStext end) as [Height Feet]
,max(case when OBSCatalogName = 'height inches NU' then OBStext end as [Height Inches]
,max(case when OBSCatalogName = 'weight kg CAL' then OBStext end as [Weight]
Rank() over (partition by VisitID, EnterDTM order by enterDTM) RNK
FROM TableName A
GROUP BY EnterDTM, VisitID)
Select  from cte where RNK = 1 

Answer 2

您可以尝试下面的数据透视查询

select
 EnterDtm,
 VisitID,
 [height feet NU] as [Height Feet],
 [height inches NU] as [Height Inches],
 [weight kg CAL] as [Weight]
from
(
  select 
    t.EnterDtm, 
    t.ObsCatalogName, 
    t.VisitID, 
    t.OBSTEXT 
 from tbl t
   inner join (select min(EnterDtm) MinDtm  from tbl) t2
   on t.EnterDtm=t2.MinDtm
)source
pivot
(
max(OBSTEXT) for ObsCatalogName in ([height feet NU],[height inches NU],[weight kg CAL])
)p