正则表达式更新日期精度

Question

我有一个包含以下日期范围格式变体的字符串。 我需要使用单个java regex模式查找并替换为小时精度。 日期范围是可变的。 你能为我想出一个正则表达式吗？

字符串示例

发布日期：{05/31 / 16.23：41：24-？}

发布日期：{05/31 / 16.23：41：24-06 / 21 / 16.23：41：24}

预期成绩

发布日期：{05/31 / 16.23：00：00-？}

发布日期：{05/31 / 16.23：00：00-06 / 21 / 16.23：00：00}

Answer 1

描述

此正则表达式将查找类似于日期/时间戳的子字符串，如05/31/16.23:41:24 。 它将捕获日期和小时部分，并允许您用00代替分钟和秒。

([0-9]{2}\/[0-9]{2}\/[0-9]{2}\.[0-9]{2}):[0-9]{2}:[0-9]{2}

替换为： $1:00:00

例

现场演示

https://regex101.com/r/qK8bL7/1

示范文本

published_date:{05/31/16.23:41:24-?}

published_date:{05/31/16.23:41:24-06/21/16.23:41:24}

更换后

published_date:{05/31/16.23:00:00-?}

published_date:{05/31/16.23:00:00-06/21/16.23:00:00}

说明

NODE                     EXPLANATION
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------
    \/                       '/'
----------------------------------------------------------------------
    [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------
    \/                       '/'
----------------------------------------------------------------------
    [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------
    \.                       '.'
----------------------------------------------------------------------
    [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  :                        ':'
----------------------------------------------------------------------
  [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------
  :                        ':'
----------------------------------------------------------------------
  [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------

Answer 2

尝试这个。 “：[0-9] +：[0-9] +”。

公共类正则表达式{

public static void main(String ar[]){
    String st = "05/31/16.23:41:24-06/21/16.23:41:24";

    st = st.replaceAll(":[0-9]+:[0-9]+", ":00:00");
    System.out.println(st);

    st = "05/31/16.23:41:24-?";

    st = st.replaceAll(":[0-9]+:[0-9]+", ":00:00");
    System.out.println(st);

}

}