如何使用JavaScript排序对树JSON对象进行双重排序？

Question

我需要param1排序z对象，然后按param2排序。 我的尝试返回重复的对象实例，其中对象参数为整数且非唯一。

我该如何解决这个问题？

z=[{object1},{object2},{object3},...,{objectN}];
z.sort(function(x,y){
    if(x.param1-y.param1>0){return -1};
    if(x.param1-y.param1<0){return 1};
    if(x.param1-y.param1==0){
        if(x.param2-y.param2>0){return -1};
        if(x.param2-y.param2<0){return 1};
    }; 

});

z类似于：

z=[{"level":0,"order":0,"t":"section","a":{"class":"ro s-14 m-3"}},
    {"level":1,"order":0,"t":"h1","a":{"class":"tx-1 s-35"},"x":"This is a text"},
    {"level":1,"order":1,"t":"div","a":{"class":"tx-0 m-3"}},
        {"level":2,"order":0,"t":"h2","a":{"class":"tx-0 s-18"},"x":"This is a text"},
        {"level":2,"order":1,"t":"h3","a":{"class":"tx-0 s-14 fw-3"}},
            {"level":3,"order":0,"t":"li","x":"This is a text"},
            {"level":3,"order":1,"t":"li","x":"This is a text"},
            {"level":3,"order":2,"t":"li","x":"This is a text"},
            {"level":3,"order":3,"t":"li","x":"This is a text"},
            {"level":3,"order":4,"t":"li","x":"This is a text"},
            {"level":3,"order":5,"t":"li","x":"This is a text"},
            {"level":3,"order":6,"t":"li","x":"This is a text"},
            {"level":3,"order":7,"t":"li","x":"This is a text"},
            {"level":3,"order":8,"t":"li","x":"This is a text"},
        {"level":2,"order":2,"t":"h4","x":"This is a text"},
    {"level":1,"order":2,"t":"div","a":{"class":"tx-0 m-3"}},
        {"level":2,"order":0,"t":"h2","x":"This is a text"},
        {"level":2,"order":1,"t":"h3","a":{"class":"tx-0 s-12 fw-3"}},
            {"level":3,"order":0,"t":"li","x":"This is a text"},
            {"level":3,"order":1,"t":"li","x":"This is a text"},
            {"level":3,"order":2,"t":"li","x":"This is a text"},
            {"level":3,"order":3,"t":"li","x":"This is a text"},
            {"level":3,"order":4,"t":"li","x":"This is a text"},
            {"level":3,"order":5,"t":"li","x":"This is a text"},
            {"level":3,"order":6,"t":"li","x":"This is a text"},
            {"level":3,"order":7,"t":"li","x":"This is a text"},
            {"level":3,"order":8,"t":"li","x":"This is a text"},
            {"level":3,"order":9,"t":"li","x":"This is a text"},
            {"level":3,"order":10,"t":"li","x":"This is a text"},
            {"level":3,"order":11,"t":"li","x":"This is a text"},
        {"level":2,"order":2,"t":"h4","x":"This is a text"},
];

Answer 1

您的实现问题是对于param1和param2 ，如果返回值不正确，则您执行相同的操作。 您的更正将是：

z = [ { object1 }, { object2 }, { object3 },...,{ objectN }];
z.sort(function(x,y){
    if(x.param1-y.param1>0){return -1};
    if(x.param1-y.param1<0){return 1};
    if(x.param1-y.param1==0){
        if(x.param2-y.param2>0){return -1};
        if(x.param2-y.param2<0){return 1};
    }; 

});

顺便说一句，我比您更喜欢这个：

 var items = [{ p1: 10, p2: 3 }, { p1: 9, p2: 4 }, { p1: 9, p2: 3 }, { p1: 10, p2: 2 }, { p1: 11, p2: 3 }, ]; items.sort((a, b) => (a.p1 - b.p1) || (a.p2 - b.p2)); console.log(items); 

如您所见，值的差异对排序函数很有意义，该函数允许您传递减法结果以用于排序。 如果difference为0（也意味着是false），那么它将用于第二个参数并返回其减法结果。

Answer 2

您可以对升序使用更紧凑的回调：

z.sort(function (x, y) {
    return x.param1 - y.param1 || x.param2 - y.param2;
});

或降序：

z.sort(function (x, y) {
    return y.param1 - x.param1 || y.param2 - x.param2;
});