如何在UI选择值中选择值？

Question

您能告诉我如何在UI选择值中选择值吗？

实际上，当用户选择任何名称时，我想选择商品的年龄 。这是我的代码http://plnkr.co/edit/InxOyQRjrlrDJtx2VuzI?p=preview

<ui-select tagging tagging-label="new tag" multiple ng-model="multipleDemo" theme="select2" ng-disabled="disabled" style="width: 300px;">
    <ui-select-match placeholder="Select colors...">{{$item.name}}</ui-select-match>
    <ui-select-choices repeat="color in people | filter:$select.search">
      {{color.name}}
    </ui-select-choices>
  </ui-select>

例

当我选择Amalie MultipleDemo模型值是12或如果我选择Wladimir是模型值“ 30” ..它是多重选择的，因此模型应该是数组..

我们能做到吗？

Answer 1

ui-select设计方法，它需要ng-model值作为object 。 在这里你给了一个原始类型

码

$scope.model = {multipleDemo :[]};

HTML

<ui-select tagging tagging-label="new tag" multiple ng-model="model.multipleDemo" theme="select2" ng-disabled="disabled" style="width: 300px;">
    <ui-select-match placeholder="Select colors...">{{$item.name}}</ui-select-match>
    <ui-select-choices repeat="color.age as color in people | filter:$select.search">
      {{color.name}}
    </ui-select-choices>
</ui-select>
<p>Selected: {{test.multipleDemo}}</p>

Plunkr

Answer 2

UI更改只需在ui-select上添加on-select="OnClickSelect($item)"和on-remove="OnRemoveSelect($item)"

      <ui-select tagging tagging-label="new tag" multiple ng-model="multipleDemo" 
          on-select="OnClickSelect($item)" on-remove="OnRemoveSelect($item)"
          theme="select2" ng-disabled="disabled" style="width: 300px;">
        <ui-select-match placeholder="Select colors...">{{$item.name}}</ui-select-match>
        <ui-select-choices  repeat="color in people | filter:$select.search">
          {{color.name}}
        </ui-select-choices>
      </ui-select>
      <p>Selected: {{multipleDemo}}</p>

角度更改在controller内部添加这些功能

  $scope.OnClickSelect=function(item)   {
    $scope.multipleDemo.push(item.age)
  }

 $scope.OnRemoveSelect = function(item) { 
   var index = $scope.multipleDemo.indexOf(item.age);
   $scope.multipleDemo.splice(index, 1);     
 }

plnkr