[英]Oracle - Subqueries reduction in Merge
我正在合并带有要获取和ID的subquery
的MERGE
,我想知道subquery in the NOT MATCHED statement
的subquery in the NOT MATCHED statement
是否始终执行。
MERGE INTO CAR_STOCK st
USING CAR_PRODUCTO pro
ON (pro.id = st.producto_id AND pro.ean = ?)
WHEN MATCHED THEN
UPDATE SET st.stockActual = ?
WHEN NOT MATCHED THEN
INSERT (stockActual, local_id, producto_id, activo)
VALUES (?, ?, (SELECT id FROM car_producto WHERE ean = ?), 'S');
谢谢!
编辑: ?
是因为我在PreparedStatement
使用JDBC
。
无需子查询,您只需在insert
部分中引用pro.id
,如下所示:
merge into t1 using t2 on (t1.a = t2.a)
when matched then update set t1.b = t2.b
when not matched then insert (a, b)
values (0, t2.b)
测试数据和merge
结果:
create table t1 as (select 1 a, 'a01' b from dual);
create table t2 as (select 1 a, 'a05' b from dual union all select 2 a, 'bxx' b from dual );
A B
------ ---
1 a05
0 bxx
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