sql与动态输入集相交

Question

我试图弄清楚如何获得动态输入集的交集。 这是一个非常简化的示例。

company_status表：

COMPANY | STATUS
----------------
  Big   |   1
Notused |   0
 Small  |   1

company_country表：

COMPANY | COUNTRY
-----------------
  Big   |   CA
  Big   |   US
Notused |   CA
Notused |   FR
 Small  |   US
 Small  |   IT

我想要的是仅针对某些公司的国家/地区交叉点。

如果我仅选择status = 1 ，则这是我的预期输出：

我们

如果我仅选择status = 0 ，这是我的预期输出：

认证机构
FR

从方程式中取出company_status表，这就是我需要的：

select country from company_status where company = 'Big'
intersect
-- ... (here is where the dynamic part comes in)
intersect
select country from company_status where company = 'Small';

但是，如何在其中添加company_status？

Answer 1

基本查询是：

select cc.country
from company_country cc join
     company_status cs
     on cc.company = cs.company
group by cc.country

然后使用having子句进行过滤。 我认为这两个过滤器是：

having min(status) = max(status) and min(status) = 1
having sum(case when status = 0 then 1 else 0 end) > 0

这些对应于示例中指定的结果集。

Answer 2

如果我理解正确，那么您只需要在company_status的每一行中满足条件status = 1或status = 0的这些国家/地区。

如果可以的话，您可以计数，在company_status中可以找到多少个外观，并在having-子句中使用它。 但是，您当然必须将相同的条件放入联接的where-子句中。

WITH 
company_status as (
  select 'BIG' COMPANY, 1 STATUS from dual union all
  select 'NOTUSED' COMPANY, 0 STATUS from dual union all
  select 'SMALL' COMPANY, 1 STATUS from dual
),
company_country as (
  select 'BIG' COMPANY, 'CA' COUNTRY from dual union all
  select 'BIG' COMPANY, 'US' COUNTRY from dual union all
  select 'NOTUSED' COMPANY, 'CA' COUNTRY from dual union all
  select 'NOTUSED' COMPANY, 'FR' COUNTRY from dual union all
  select 'SMALL' COMPANY, 'US' COUNTRY from dual union all
  select 'SMALL' COMPANY, 'IT' COUNTRY from dual
)
select cc.country
from company_country cc join
     company_status cs
     on cc.company = cs.company
where cs.status = 0
group by cc.country
having count(*) = (SELECT COUNT(*) FROM company_status where status = 0);

（with-子句仅提供您的行，其余的问题应在您的示例中起作用）

但是，您可以使用with-子句确定仅在一个位置上想要的状态（第三个with-子句将是您的第一个）：

WITH 
company_status as (
  select 'BIG' COMPANY, 1 STATUS from dual union all
  select 'NOTUSED' COMPANY, 0 STATUS from dual union all
  select 'SMALL' COMPANY, 1 STATUS from dual
),
company_country as (
  select 'BIG' COMPANY, 'CA' COUNTRY from dual union all
  select 'BIG' COMPANY, 'US' COUNTRY from dual union all
  select 'NOTUSED' COMPANY, 'CA' COUNTRY from dual union all
  select 'NOTUSED' COMPANY, 'FR' COUNTRY from dual union all
  select 'SMALL' COMPANY, 'US' COUNTRY from dual union all
  select 'SMALL' COMPANY, 'IT' COUNTRY from dual
),
wished_status as (select 0 wished_status from dual)
select cc.country
from company_country cc 
join company_status cs on cc.company = cs.company
JOIN wished_status s on cs.status = s.wished_status
group by cc.country
having count(*) = (SELECT COUNT(*) FROM company_status cs join wished_status s on cs.status = s.wished_status);

因此您只需要在wished_status 0到1（或任何您需要的值）之间进行wished_status