使用 Google-Drive-API 移动文件

Question

是否可以通过 python 的 googleapiclient 模块显式移动文件？ 我想创建以下函数，给定文件、原始路径和目标路径：

def move_file(service, filename, init_drive_path, drive_path, copy=False):
    """Moves a file in Google Drive from one location to another.

    service: Drive API service instance.
    filename (string): full name of file on drive
    init_drive_path (string): initial file location on Drive
    drive_path (string): the file path to move the file in on Drive
    copy (boolean): file should be saved in both locations

    Returns nothing.
    """

目前，我一直通过手动下载文件然后将其重新上传到所需位置来执行此操作，但是这对于大文件来说并不实用，无论如何似乎都是一种解决方法。

这是google-drive-api 上可用方法的文档。

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编辑请参阅下面的解决方案：

Answer 1

在这里找到了。 您只需要检索文件和文件夹 ID，然后使用更新方法。 如果您想在旧文件夹中保留文件的副本，可以排除 remove_parents 参数

    file_id = '***'
    folder_id = '***'

    # Retrieve the existing parents to remove
    file = drive_service.files().get(fileId=file_id, fields='parents').execute()
    previous_parents = ",".join(file.get('parents'))

    # Move the file to the new folder
    file = drive_service.files().update(
        fileId=file_id,
        addParents=folder_id,
        removeParents=previous_parents,
        fields='id, parents'
    ).execute()

（注意我没有包括我的基本辅助函数 _getFileId 和 _getFolderId）所以我的原始函数看起来像：

    def move_file(service, filename, init_drive_path, drive_path, copy=False):
        """Moves a file in Google Drive from one location to another.
    
            service: Drive API service instance.
            'filename' (string): file path on local machine, or a bytestream
            to use as a file.
            'init_drive_path' (string): the file path the file was initially in on Google
            Drive (in <folder>/<folder>/<folder> format).
            'drive_path' (string): the file path to move the file in on Google
            Drive (in <folder>/<folder>/<folder> format).
            'copy' (boolean): file should be saved in both locations
    
            Returns nothing.
        """
        file_id = _getFileId(service, filename, init_drive_path)
        folder_id = _getFolderId(service, drive_path)
    
        if not file_id or not folder_id:
            raise Exception('Did not find file specefied: {}/{}'.format(init_drive_path, filename))
    
        file = service.files().get(fileId=file_id, fields='parents').execute()
        
        if copy:
            previous_parents = ''
        else:
            previous_parents = ",".join(file.get('parents'))

        file = drive_service.files().update(
            fileId=file_id,
            addParents=folder_id,
            removeParents=previous_parents,
            fields='id, parents'
        ).execute()