在java中绘制/擦除按钮

Question

我正在努力找到一种方法来实现一种方法，无论何时单击绘图按钮，它将决定您是绘图还是删除。

 private void drawButtonActionPerformed (java.awt.event.ActionEvent evt) {

        solveButton.setEnabled(true);

        slider.setEnabled(true);

        captureButton.setEnabled(true);

    } 

我的代码现在可以自动决定是否根据您点击的障碍物进行绘制或擦除

 private class MouseHandler implements MouseListener, MouseMotionListener {

        int cur_row, cur_col, cur_val;



        @Override
        public void mousePressed(MouseEvent evt) {


            int row = (evt.getY() - 10) / squareSize;
            int col = (evt.getX() - 10) / squareSize;
            if (row >= 0 && row < rows && col >= 0 && col < columns) {

                cur_row = row;
                cur_col = col;
                cur_val = grid[row][col];

                if (cur_val == EMPTY) {
                    grid[row][col] = OBST;
                }
                if (cur_val == OBST) {
                    grid[row][col] = EMPTY;
                }
                repaint();
            }
        }

        @Override
        public void mouseDragged(MouseEvent evt) {

            int row = (evt.getY() - 10) / squareSize;
            int col = (evt.getX() - 10) / squareSize;
            if (row >= 0 && row < rows && col >= 0 && col < columns) {

                if ((row * columns + col != cur_row * columns + cur_col) && (cur_val == STARTNODE || cur_val == ENDNODE)) {
                    int new_val = grid[row][col];
                    if (new_val == EMPTY) {
                        grid[row][col] = cur_val;
                        if (cur_val == STARTNODE) {
                            startnodeStart.row = row;
                            startnodeStart.col = col;
                        } else {
                            endnodePos.row = row;
                            endnodePos.col = col;
                        }
                        grid[cur_row][cur_col] = new_val;
                        cur_row = row;
                        cur_col = col;
                        if (cur_val == STARTNODE) {
                            startnodeStart.row = cur_row;
                            startnodeStart.col = cur_col;
                        } else {
                            endnodePos.row = cur_row;
                            endnodePos.col = cur_col;
                        }
                        cur_val = grid[row][col];
                    }
                } else if (grid[row][col] != STARTNODE && grid[row][col] != ENDNODE) {
                    grid[row][col] = OBST;
                }

            }

            repaint();

        }

        @Override
        public void mouseReleased(MouseEvent evt) {
        }

        @Override
        public void mouseEntered(MouseEvent evt) {
        }

        @Override
        public void mouseExited(MouseEvent evt) {
        }

        @Override
        public void mouseMoved(MouseEvent evt) {
        }

        @Override
        public void mouseClicked(MouseEvent evt) {
        }

    }

请帮助我谢谢。

Answer 1

我没有阅读代码（它很长很不清楚），但是如果你想做我想你想做的事情（有一个程序，你可以绘制然后稀疏你绘制的东西）你可以画出圈子按下鼠标按钮时鼠标的x和y中的某种颜色。 当你想要简化时，你只需要用背景颜色做同样的事情。