将键映射到Python字典中的值

Question

正在努力使字典键和值正确排列。

import pprint

old_dict = {'A B':['C D'],'E F':['G H'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']}
new_dict = {}

for x in old_dict:
    try:
        for i in range(0,2):
            key = x.split()[i]
            value = old_dict[x][0].split()[i]
            new_dict[key] = value
    except:
        pass

pprint.pprint(new_dict)

上面的代码可以正常工作并返回：

{'A': 'C',
 'B': 'D',
 'E': 'G',
 'F': 'H',
 'I': 'K',
 'J': 'L',
 'M': 'O',
 'N': 'P',
 'Q': 'S',
 'R': 'T',
 'U': 'W',
 'V': 'X'}

唯一的问题是，当我将old_dict更改为以下内容时：

old_dict = {'AB':['C D'],'E F':['GH'],'IJ':['KL'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']}

它返回：

{'AB': 'C',
 'E': 'GH',
 'IJ': 'KL',
 'M': 'O',
 'N': 'P',
 'Q': 'S',
 'R': 'T',
 'U': 'W',
 'V': 'X'}

我想跳过不是以空格分隔的键与空格分隔的值配对的键，也要跳过不是以空格分隔的键与空格分隔的键配对的值（即，我想跳过'AB'： 'C'，'E'：'GH'，-上面示例中的其余部分都可以）。

我该怎么办？

Answer 1

我正在手机上执行此操作，因此我现在无法真正对其进行测试，但这应该可以做到：

d = {'A B':['C D'],'E F':['G H'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']}
answer = {}

for k in d:
    k = k.split()
    if len(k) == 1: continue
    v = d[k][0].split()
    if len(v) == 1: continue

    for a,b in zip(k,v):
        answer[a] = b

Answer 2

经过测试可以正常工作：

import pprint

old_dict = {'AB':['C D'],'E F':['GH'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']}
new_dict = {}

for x in old_dict:
    try:
        for i in range(0,2):
            key = x.split()[i]
            if len(key) == 1:
                if len(old_dict[x][0].split()[i]) == 1:
                    value = old_dict[x][0].split()[i]
            new_dict[key] = value
    except:
        pass

pprint.pprint(new_dict)

Answer 3

import pprint

old_dict = {'AB':['C D'],'E F':['GH'],'IJ':['KL'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']}
new_dict = {}

for x in old_dict:
    try:
        if(len(x)==len(old_dict[x][0])):
            for i in range(0,2):
                key = x.split()[i]
                value = old_dict[x][0].split()[i]
                new_dict[key] = value
    except:
        pass


pprint.pprint(new_dict)

Answer 4

您可以使用dict理解：

>>> old_dict = {'AB':['C D'],'E F':['GH'],'IJ':['KL'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']}
>>> {x: y for k, v in old_dict.items() if len(k) == len(v[0]) for x, y in zip(k.split(), v[0].split())}
{'M': 'O', 'N': 'P', 'Q': 'S', 'IJ': 'KL', 'U': 'W', 'V': 'X', 'R': 'T'}

Answer 5

尝试这个：

import pprint
old_dict = {'AB':['C D'],'E F':['GH'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']}
new_dict = {}

for x in old_dict:
    for i in range(0,2):
      if ' ' in x:
        key = x.split()[i]
      else:
        key = x.replace("", " ")[1:-1]
        key = key.split()[i]
      if ' ' in old_dict[x][0]:
        value = old_dict[x][0].split()[i]
      else:
        value = old_dict[x][0].replace("", " ")[1:-1]
        value = value.split()[i]

      new_dict[key] = value

pprint.pprint(new_dict)