如何获取返回的每个项目的行号

Question

我正在尝试使用XSwitch jquery脚本并动态地自动创建“部分ID”，但被卡住了。

如何给每个部分一个从0开始的“ id”？ 有些项目有2或3张图片，有些则有30张以上。

$result = mysqli_query($conn,"SELECT * FROM Images WHERE stock=".$_GET['stock']." ORDER BY orderIndex");
while($row = mysqli_fetch_array($result)){
  $count = $result->num_rows;
  if ($count) {
    $photos .= '<div class="section" id="section__NEED___NUMBER" style="background-image: url(inventory/'.$category.'/large/'.$stock.'_'.$row['id'].'.jpg)"></div>';
  } else {
    $photos = 'No Photos are currently available';
  }
}

Answer 1

您可以使用一个简单的计数器变量（ $counter = 0; ），您可以在每个循环中将其增加（$ counter ++;`）-

$counter = 0;
$result = mysqli_query($conn,"SELECT * FROM Images WHERE stock=".$_GET['stock']." ORDER BY orderIndex");
$count = $result->num_rows;
if ($count) {
    $photos = "";
    while($row = mysqli_fetch_array($result)){
        $photos .= '<div class="section" id="section__'.$counter.'" style="background-image: url(inventory/'.$category.'/large/'.$stock.'_'.$row['id'].'.jpg)"></div>';
        $counter++;
    }
} else {
    $photos = 'No Photos are currently available';
}

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注意，您的$count = $result->num_rows;if ($count) {...}在while()循环内，何时应该在外面。