使用正则表达式的Python 3

Question

我需要查看一个字符串，然后使用正则表达式来将数据存储在变量中

这是一个字符串的示例：我必须存储以下数据：

"www","7/27/2016","3:00pm",21.00,N/A,N/A,"12.90 - 21.75",N/A,+0.00,0,N/A

到目前为止，我可以存储第一个符号的日期和时间以及第一个数字，但是我不知道如何遍历字符串的其余部分并存储数字

symb = re.match(r'"(.*?)"', line) #line is the line of string

if symb is not None:
    print(symb.group(1))
    print()

else:
    print("No Match")
    print()

date = re.match(r'".+?(\d+/\d+/\d+)"', line)

if date is not None:
    print(date.group(1))
    print()

else:
    return print("No Match")
    print()

time = re.match(r'".+?(\d+:\d+[a-z]{2})"', line)

if time is not None:
    print(time.group(1))
    print()

else:
    print("No Match")
    print()

 #lastPrice = The first number after the time  
lastPrice = re.match(r'.+?(\d+\.\d{2}?),', line)

if lastPrice is not None:
    print(lastPrice.group(1))
    print()

else:
    print("No Match")
    print()

Answer 1

import re

text = '"www","7/27/2016","3:00pm",21.00,N/A,N/A,"12.90 - 21.75",N/A,+0.00,0,N/A'
regex = r'.*?,"(\d+/\d+/\d{4})","(\d+:\d{2}\w{2})",(\d+\.\d+),N/A,N/A,"(\d+\.\d+) - (\d+\.\d+)",N/A,(\+\d+\.\d+),0,N/A'
listofmatches = re.findall(regex, text)

假设您有多个数据。 否则，仅对第一个数据使用listofmatches[0]

for lines in listofmatches:
    date, time, price, a, b, c = lines
    # do something with variables

或将re.findall替换为re.search

listofmatches = re.search(regex, text)
date, time, price, a, b, c = listofmatches.groups()
print(date)