java regex查找字符串中的单词，查找符号如。，！（？和空格的空字符串

Question

这是我的情况字符串：

"This is a test.  How many???  " + "Senteeeeeeeeeences are here... there should be 5!  Right?"

使用String[] words = getText().split("[( +)!.?,]");

我得到这个数组： [This, is, a, test, , , How, many, , , , , Senteeeeeeeeeences, are, here, , , , there, should, be, 5, , , Right

如何消除空字符串？

Answer 1

您的问题还不够清楚。
如果不是您告诉我的那样，那么我可以更新答案或删除它。

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您只需要全局匹配所有非单词 。 而已。

你需要什么
[^\\w]+

它是如何工作的
对于拆分，它匹配除[a-zA-Z0-9_]之外的所有内容。

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证明

快速测试

echo "This is a test.  How many???  " + "
 Senteeeeeeeeeences are here... there should 
 be 5!  Right?" | perl -lne 'print "@{[split( /[^\w]+/g )]}"'  

产量
This is a test How many Senteeeeeeeeeences are here there should be 5 Right

Answer 2

String stringToSearch = "This is a test.  How many???  " + "Senteeeeeeeeeences are here... there should be 5!  Right?";

Pattern p1 = Pattern.compile("[\\W]+");
String[] str = p1.split(stringToSearch);
System.out.println(Arrays.asList(str));

输出：

[这是一个测试，有多少，应该有5个，正确，有多少个Senteeeeeeeeences，这是正确的]