使用 Bugzilla Restful Api 在 Bugzilla 中创建错误

Question

使用restful webservice API在Bugzilla中创建新错误的任何示例代码？ 到目前为止，我所做的是使用 Postman 来查看它是如何工作的：

简单的json代码：

{
    "product" : "TestProduct",
    "component" : "TestComponent",
    "summary" : "This is the best bug report",
    "version" : "unspecified",
    "description" : "This is the best GUI for reporting bugs"
}

这是端点：

http://localhost/bugzilla/rest.cgi/rest/bug

我得到的错误日志：

{
  "code": 32614,
  "message": "A REST API resource was not found for 'POST /rest/bug'.",
  "documentation": "https://bugzilla.readthedocs.org/en/5.0/api/",
  "error": true
}

Answer 1

一个用 python 编写的示例示例，使用其余 API 在 Bugzilla 5.x 中创建错误。

import requests

data = {
    "product" : "TestProduct",
    "component" : "TestComponent",
    "summary" : "This is the best bug report",
    "version" : "unspecified",
    "description" : "This is the best GUI for reporting bugs"
}
url_bz_restapi = 'http://localhost/bugzilla/rest.cgi/bug'
r = requests.post(url_bz_restapi, data=data)

Answer 2

从 api " /rest/login?login=foo@example.com&password=toosecrettoshow " 创建一个新令牌

import requests

url = 'http://localhost/bugzilla/rest.cgi/bug?token=GENERATED TOKEN' 
data = {   
"product" : "TestProduct",   
"component" : "TestComponent", 
"version" : "unspecified",   
"summary" : "'This is a test bug - please disregard",   
"alias" : "Somlias",   
"op_sys" : "All",  
"priority" : "---",   
"rep_platform" : "All" 
}

def create_bug(url,data):   
    test = requests.post(url,data=data)     
    return test.json()

create_bug(url,data)

Answer 3

使用休息客户端

网址：HTTP：// IP /bugzilla/rest.cgi/bug

方法：POST

基本身份验证：令牌： gentoken

JSON :

{

"product" : "Ashok",

“组件”：“测试”，

“版本”：“未指定”，

"summary" : "'这是一个测试错误 - 来自 JSON"

}