编号MySQL结果

Question

使用以下MySQL查询：

    SELECT  SUM(vg.count) AS sum, vg.code, lh.luchthavencode
    FROM 
    (
    SELECT COUNT( * ) AS COUNT, vg.vertrekluchthaven AS code
    FROM tbl_vluchtgegevens vg
    WHERE vg.vertrekdatum2 <= NOW( ) 
    GROUP BY vg.vertrekluchthaven

    UNION  

        SELECT COUNT(*) AS COUNT, vg.aankomstluchthaven AS code
        FROM tbl_vluchtgegevens vg  
        WHERE vg.vertrekdatum2 <=NOW()
        GROUP BY vg.aankomstluchthaven
    ) vg
    INNER JOIN tbl_luchthaven lh
    ON  lh.luchthavenID = vg.code
    GROUP BY vg.code
    ORDER BY sum DESC
    LIMIT 10

我试图弄清楚如何对结果进行编号，以便在将它们显示在PHP页面上时，更容易理解结果。

例如，当前我的结果将显示如下内容：

Sum   |   Code  |   Luchthavencode
41        121             MSP
26        91              AMS
9         246             ORD
8         116             DTW
6         169             LHR
6         142             IAH
6         346             SYR
5         149             JFK
5         13              AKL
5         417             FRA 

我想要的是这样的清单：

No. |   Sum   |   Code  |   Luchthavencode
1       41        121             MSP
2       26        91              AMS
3       9         246             ORD
4       8         116             DTW
5       6         169             LHR
6       6         142             IAH
7       6         346             SYR
8       5         149             JFK
9       5         13              AKL
10      5         417             FRA 

这是通过MySQL查询还是PHP输出最好地实现？

我尝试将其添加到我的SELECT（@row_number：= @ row_number + 1）AS num中，但它像这样对它们进行编号：45、4、47、18、34、24、56、27、2、63

编辑以包含输出PHP：

while($row = mysqli_fetch_assoc($result)) {

    echo"  <table width='100px' border='0' cellpadding='1' cellspacing='1'>";
    echo "  <tbody>";
    echo "    <tr>";
    echo "      <td width='60px'><strong>&nbsp; &nbsp;".$row['luchthavencode']."</strong></td>";
    echo "      <td width='30px'><strong>&nbsp; &nbsp;".$row['sum']."</strong></td>";
    echo "    </tr>";
    echo "  </tbody>";
    echo "</table>";    
}

Answer 1

在查询开始时使用此代码来获取行数

SELECT @rownum:=@rownum+1 AS rownum

Answer 2

使用变量应该可以，请尝试以下检查是否可行：

SELECT
    @rowno := @rowno + 1 AS `No.`
    SUM(vg.count) AS sum,
    vg. CODE,
    lh.luchthavencode
FROM
    (
        SELECT
            COUNT(*) AS COUNT,
            vg.vertrekluchthaven AS CODE
        FROM
            tbl_vluchtgegevens vg
        WHERE
            vg.vertrekdatum2 <= NOW()
        GROUP BY
            vg.vertrekluchthaven
        UNION
        SELECT
            COUNT(*) AS COUNT,
            vg.aankomstluchthaven AS CODE
        FROM
            tbl_vluchtgegevens vg
        WHERE
            vg.vertrekdatum2 <= NOW()
        GROUP BY
            vg.aankomstluchthaven
    ) vg
INNER JOIN tbl_luchthaven lh ON lh.luchthavenID = vg.CODE
CROSS JOIN (SELECT @rowno := 0) rn
GROUP BY
    vg. CODE
ORDER BY
    sum DESC
LIMIT 10

Answer 3

我假设您想要一个包含此数据的表，所以我修复了我认为是表构建中的错误以及添加了一个计数器的问题

echo "<table width='100px' border='0' cellpadding='1' cellspacing='1'>";
echo "<tbody>";

$line = 1;

while($row = mysqli_fetch_assoc($result)) {

    echo "<tr>";
    echo "<td>$line</td>";
    echo "<td width='60px'><strong>&nbsp; &nbsp;".$row['luchthavencode']."</strong></td>";
    echo "<td width='30px'><strong>&nbsp; &nbsp;".$row['sum']."</strong></td>";
    echo "</tr>";

    $line++;
}

echo "</tbody>";
echo "</table>";