将XML内容插入到mysql DB中

Question

基本上我有一个调用外部XML文件的php脚本

然后它将来自xml文件的某些数据插入到foreach循环内的mysql数据库中

但是当我检查数据库时它是空的

我究竟做错了什么

xml包含以下结构

<jobs>
    <job>
        <jobref>987654321</jobref>
        <title>TITLE HERE</title>
        <url>
        URL HERE
        </url>
        <salary>&pound;85 - &pound;105/day benifits</salary>
        <location>LOCATION</location>
        <description>desc</description>
        <category>CAT HERE</category>
    </job>
    <job>
        <jobref>123456789</jobref>
        <titleTITLE HERE</title>
        <url>
        URL HERE
        </url>
        <salary>&pound;85 - &pound;105/day benifits</salary>
        <location>LOCATION</location>
        <description>desc</description>
        <category>CAT</category>
    </job>
</jobs>

下面是PHP代码

<?php
    $dbu = 'user';
    $dbp = 'pass';
    $dbh = 'localhost';
    $dbn = 'dbname';

    $dbc = mysql_pconnect($dbh,$dbu,$dbp);

    // Get XML Feed
    $startPage = $_GET['page'];
    $perPage = 3000;
    $currentRecord = 0;
    $xml = simplexml_load_file("urlhere");
    $jobs = $xml->xpath("/jobs/job");

    foreach ($jobs as $job)
    {
        mysql_select_db($dbn,$dbc);
        $query = mysql_query("INSERT INTO `listings` (`jobref`,`title`,`url`,`salary`,`location`,`description`,`category`) VALUES ('$job->jobref','$job->title','$job->salary','$job->location','$job->description','$job->category')",$dbc);

        echo "$job->jobref Added <br>";
    }
?>

它显示：

120239811 Added 
201909016 Added 
202482907 Added 

当我运行脚本所以它解析xml文件但它实际上没有插入数据

任何帮助都会很棒，因为我在一个非常紧迫的时间内完成了这个提前谢谢

**以下编辑**以下新代码

<?php
        $startPage = 1;
        $perPage = 3000;
        $currentRecord = 0;
        $xml = simplexml_load_file("urlhere");
        $jobs = $xml->xpath("/jobs/job");
        mysql_select_db($dbn,$dbc);
        foreach ($jobs as $job)
        {
        $currentRecord += 1;
         if($currentRecord > ($startPage * $perPage) && $currentRecord < ($startPage * $perPage + $perPage)){ 
        $query = mysql_query("INSERT IGNORE INTO `listings` (jobref,title,url,salary,location,description,category) VALUES ('$job->jobref','$job->title','$job->url','$job->salary','$job->location','$job->description','$job->category')",$dbc);
        if($query){
        echo "$job->jobref Added <br>";
        } else {
        echo mysql_error();
        }
        }
        }
        ?>

它现在只是在XML文件中添加第一个条目

从查询中删除了IGNORE并添加了ON DUPLICATE KEY UPDATE jobref = $ job-> jobref + 1仍然是同样的问题

Answer 1

你确定xml成功加载了吗？ :)但我猜你的样本中的xml节点<salary>有非法的＆符号"&" 这里有关于它的链接 。

但你可以处理它与一个小黑客这样 。

我建议你使用mysqli ，所以根据你的xml样本

...

$conn = mysqli_connect($dbh, $dbu, $dbp);
if(!$conn) die('connect fail: '. mysqli_error($conn));

$db = mysqli_select_db($conn, $dbn);
if(!$db) die('db fail: '. mysqli_error($conn));

... 

$file = file_get_contents(url_here);

// replace '&' to '&'
$file = str_replace('&', '&', $file);
$xml = simplexml_load_string($file);

$jobs = $xml->xpath("/jobs/job");

foreach ($jobs as $job)
{
    ...

    // just get back those ampersand
    $job->salary = str_replace('&', '&', $job->salary);

    $s = "INSERT IGNORE INTO `listings` (`jobref`,`title`,`url`,`salary`,`location`,`description`,`category`) VALUES('$job->jobref','$job->title','$job->url','$job->salary','$job->location','$job->description','$job->category')";

    $q = mysqli_query($conn, $s);

    if(!$q) {
        die(mysqli_error($conn));
    }else {
        echo "$job->jobref Added <br>";
    }
}