Json解析并总结了json中的值

Question

我有一组json值，如下所示

{"labels":[ "time", "softirq", "user", "system", "nice", "iowait" ], "data":[ [ 1490088352, 0, 14.64646, 3.53535, 0, 1.0101 ], [ 1490088351, 0, 27.77778, 3.0303, 0, 0 ], [ 1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761 ] }

我想解析这个json .sum up标签{ "softirq", "user", "system", "nice", "iowait"}值并存储在名为“sum”的单独值中。 我的最终输出应如下所示：

{ "time" : 1490088352 , "sum": "the value which we added "}
{"time" : 1490088351 , "sum": "the value which we added "}
{"time" : 1490088350 , "sum": "the value which we added "}

任何人都可以帮我解决这个问题吗？

Answer 1

使用Array#reduce将数组Array#reduce为单个值

Array.slice(1)将返回不包括第一个值的数组

 var data = { "labels": ["time", "softirq", "user", "system", "nice", "iowait"], "data": [ [1490088352, 0, 14.64646, 3.53535, 0, 1.0101], [1490088351, 0, 27.77778, 3.0303, 0, 0], [1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761] ] }; var op = []; data.data.forEach(function(el) { var obj = { time: el[0] }; obj.sum = el.slice(1).reduce(function(a, b) { return a + b; }); op.push(obj); }); console.log(op); 

Answer 2

怎么样，首先加载数据，

var values= {
  "labels": ["time", "softirq", "user", "system", "nice", "iowait"],
  "data": [
    [1490088352, 0, 14.64646, 3.53535, 0, 1.0101],
    [1490088351, 0, 27.77778, 3.0303, 0, 0],
    [1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761]
  ]
};

然后，

var answer = values.data.map(function(d){return {"time":d[0], "sum": d.splice(1,d.length).reduce((a, b) => a + b, 0)};});

Answer 3

    var source = {
  "labels": ["time", "softirq", "user", "system", "nice", "iowait"],
  "data": [
    [1490088352, 0, 14.64646, 3.53535, 0, 1.0101],
    [1490088351, 0, 27.77778, 3.0303, 0, 0],
    [1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761]
  ]
};

    var  data =source.data;


var mydata = [];
var eachObject={};

for(var i in data){
  sum=0;
  eachObject={};
  for(var j=1,l=data[i].length;j<l;j++ ){
    sum+=data[i][j];
  }

  eachObject.time=data[i][0];
  eachObject.sum=sum;
  mydata.push(eachObject);

  console.log(mydata);
}

Answer 4

 var arr= {"labels":[ "time", "softirq", "user", "system", "nice", "iowait" ], "data":[ [ 1490088352, 0, 14.64646, 3.53535, 0, 1.0101 ], [ 1490088351, 0, 27.77778, 3.0303, 0, 0 ], [ 1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761 ]] }; var op = []; for(var i =0; i < arr.data.length; i++){ var obj = {}; obj.time = arr.data[i][0]; obj.sum = 0; for(var j = 1; j < arr.data[i].length; j++){ obj.sum += arr.data[i][j]; } op.push(obj); } console.log(op);  var arr= {"labels":[ "time", "softirq", "user", "system", "nice", "iowait" ], "data":[ [ 1490088352, 0, 14.64646, 3.53535, 0, 1.0101 ], [ 1490088351, 0, 27.77778, 3.0303, 0, 0 ], [ 1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761 ]] }; var op = []; for(var i =0; i < arr.data.length; i++){ var obj = {}; obj.time = arr.data[i][0]; obj.sum = 0; for(var j = 1; j < arr.data[i].length; j++){ obj.sum += arr.data[i][j]; } op.push(obj); } console.log(op);  var arr= {"labels":[ "time", "softirq", "user", "system", "nice", "iowait" ], "data":[ [ 1490088352, 0, 14.64646, 3.53535, 0, 1.0101 ], [ 1490088351, 0, 27.77778, 3.0303, 0, 0 ], [ 1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761 ]] }; var op = []; for(var i =0; i < arr.data.length; i++){ var obj = {}; obj.time = arr.data[i][0]; obj.sum = 0; for(var j = 1; j < arr.data[i].length; j++){ obj.sum += arr.data[i][j]; } op.push(obj); } console.log(op); 

Answer 5

您可以使用带有所需标签的数组和用于时间分组的哈希表。

 var data = { "labels": ["time", "softirq", "user", "system", "nice", "iowait"], "data": [[1490088352, 0, 14.64646, 3.53535, 0, 1.0101], [1490088351, 0, 27.77778, 3.0303, 0, 0], [1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761]] }, labels = ["softirq", "user", "system", "nice", "iowait"], result = data.data.reduce(function (hash) { return function (r, a) { if (!hash[a[0]]) { hash[a[0]] = { time: a[0], sum: 0 }; r.push(hash[a[0]]); } hash[a[0]].sum += labels.reduce(function (r, l) { return r + (a[data.labels.indexOf(l)] || 0); }, 0); return r; }; }(Object.create(null)),[]); console.log(result); 

 .as-console-wrapper { max-height: 100% !important; top: 0; } 

Answer 6

  var data = { "labels": ["time", "softirq", "user", "system", "nice", "iowait"], "data": [ [1490088352, 0, 14.64646, 3.53535, 0, 1.0101], [1490088351, 0, 27.77778, 3.0303, 0, 0], [1490088350, 0.49751, 12.93532, 2.98508, 0, 4.47761] ] }; var op = []; for(var i = 0; i < data.data.length; i++){ var json = {"time" : data.data[i][0], "sum" : 0} for(var j = 1; j < data.data[i].length; j++){ json.sum += data.data[i][j]; } op.push(json) } console.log(op)