Python嵌套字典遍历

Question

我是python的新手，我在寻找完成任务的好方法时遇到了一些麻烦

鉴于我有一本与此相似的字典

x = {
"rackList": [
    {
        "rackType": "apc",
        "serverList": [
            {
                "serverType": "x4950",
                "serverIp": "192.168.0.1",
            }
        ],
        "position": 1
    },
    {
        "rackType": "apc",
        "serverList": [
            {
                "serverType": "x4950",
                "serverIp": "192.168.0.2",
            }
        ],
        "position": 2
    },
    {
        "rackType": "apc",
        "serverList": [
            {
                "serverType": "x4950",
                "serverIp": "192.168.0.3",
            }
        ],
        "position": 3
    },
    {
        "rackType": "apc",
        "serverList": [
            {
                "serverType": "x4950",
                "serverIp": "192.168.0.4",
            }
        ],
        "position": 4
    }
]}

我需要从每个serverList中提取服务器IP，所以目前我正在这样做：

y = []

for i in x['rackList']:
    for j in i['serverList']:
        y.append(j['serverIp'])

我想知道是否有更多的类似python或elagent的方式来达到相同的结果。

提前致谢

Answer 1

是的，这称为列表理解 ：

y = [server['serverIp'] for rack in x['rackList'] for server in rack['serverList']]
# ['192.168.0.1', '192.168.0.2', '192.168.0.3', '192.168.0.4']