Laravel上传数据库不同字段中的多个文件

Question

我试图在三个不同领域的三个图像在controller.But database..for，我是下面的方法，我面临的问题是，虽然我有三个输入字段它存储只有两个名称相同的图像在公共文件夹中，数据库它存储的值如1 (for product_image), 4 ( for vendor_image), 9 (for user_image) 。 我如何正确地将图像存储在公共文件夹和数据库中......提前致谢。

这是控制器：

public function store(Request $request)
{
    $product = new Product();
    $files= [];

    if($request->file('product_image'))   $files[] = $request->file('product_image');
    if($request->file('vendor_image'))   $files[] = $request->file('vendor_image');
    if($request->file('user_image'))     $files[] = $request->file('user_image');


      foreach($files as $file)
      {    
          if(!empty($file))
          {
              $filename = time().'.'.$file->getClientOriginalExtension();
              $file->move('images/',$filename);
          }
      }
      $product->product_image = $filename[0];
        
      $product->vendor_image = $filename[1];

      $product->user_image = $filename[2];
      $product->save();
  }

这是视图部分：

<div class="form-group">
     <label>Product Image</label>
     <input type="file" name="product_image"  id="product_image" width="200px">                                              
</div>
<div class="form-group">
     <label>Feature Image</label>
     <input type="file" name="vendor_image"  id="vendor_image" width="200px">
                                        
</div>
<div class="form-group">
     <label>Slurp Image</label>
     <input type="file" name="user_image"  id="user_image" width="200px">                                          
</div>

Answer 1

将你的名字存储到数组

    $filenames = [];
foreach($files as $file)
    {
    if (!empty($file))
        {
        $filename = time() . '.' . $file->getClientOriginalExtension();
        $file->move('images/', $filename);
        $filenames[] = $filename
        }
    }



$product->product_image = $filenames[0];
$product->vendor_image = $filenames[1];
$product->user_image = $filenames[2];
$product->save();

Answer 2

    public function imageupload(Request $request) {
        $files=[];
        if($request->file('profilePhoto')) $files[]=$request->file('profilePhoto');
        if($request->file('fssaiPhoto')) $files[]=$request->file('fssaiPhoto');
        if($request->file('panPhoto')) $files[]=$request->file('panPhoto');

        foreach($files as $file){
                $uniqid = Str::random(9);
        $fileName = $uniqid.'.'.$file->extension();  
     
        $file->move(public_path('file'), $fileName);
        
        $data[]=$fileName;
            
        } 
            $images=new fileuploadmodels;
            $images->phno=$request->phno;
            $images->profilePhoto=$data[0];
            $images->fssaiPhoto=$data[1];
            $images->panPhoto=$data[2];
            $images->save();
            return response()->json([
                "message"=>"photo upload success"
            ],201);
    }

Answer 3

尝试这个：

$product_image = NULL;
$vendor_image= NULL;
$user_image= NULL;
if($request->product_image)
{
     $product_image= time().'-'. $request->product_image->getClientOriginalName();
     $request->product_image->move(public_path('images/'),$product_image);
}
if($request->vendor_image)
{
     $vendor_image= time().'-'. $request->vendor_image->getClientOriginalName();
     $request->vendor_image->move(public_path('images/'),$vendor_image);
}
if($request->user_image)
{
     $user_image= time().'-'. $request->user_image->getClientOriginalName();
     $request->user_image->move(public_path('images/'),$user_image);
}

$product->product_image = $product_image;
        
$product->vendor_image = $vendor_image;

$product->user_image = $user_image;
$product->save();