我的回报为0，我不知道为什么

Question

我的PHP代码和SQL语句出现问题。

我想找回我的Indice的ID，其中我的名字=“ myname”。 这是我的代码：

<?php
include 'Connection.php';

try { 
    $db = new PDO("$server:host=$host;dbname=$base", $user, $passwd); 


    //Statement = INSERT INTO indice
    $stmtInd = $db->prepare("INSERT INTO indice(ID, Name, IDFormation)
        VALUES (:ID, :Name, :IDFormation)");
        $stmtInd->bindParam(':ID', $id);
        $stmtInd->bindParam(':Name', $name);
        $stmtInd->bindParam(':IDFormation', $idformation);
    //Statement = INSERT INTO note
    $stmtNote = $db->prepare("INSERT INTO note(ID, Valeur, Valeurtext, IDIndice)
        VALUES (:ID, :Valeur, :Valeurtext, :IDIndice)");
        $stmtNote->bindParam(':ID', $ID);
        $stmtNote->bindParam(':Valeur', $valeur);
        $stmtNote->bindParam(':Valeurtext', $valeurtext);
        $stmtNote->bindParam(':IDIndice', $IDindice);
    $noteIdindice = $db->prepare("SELECT ID FROM indice WHERE Name = :Name");
        $noteIdindice->bindParam(':Name', $name);
        $noteIdindice->execute();           
        $resultat = $noteIdindice->fetch(\PDO::FETCH_ASSOC);    
        var_dump($resultat);

    //Indice 1
    $name = "Equilibre theorie / pratique";
    $idformation = "1";
    $stmtInd->execute();

    $valeur = $_POST["indice1"];
    $valeurtext = "";
    $IDindice = $resultat['ID'];
    $stmtNote->execute();
    echo "Success";
} 
catch (PDOException $e) { 
    die("Impossible de se connecter a la source de donnees..."); 
}
?>

还有其他的Indice，但您不需要它，因为它与“ // Indice 1”相同。

一切正常，我没有失败。 但是我的查询给了我错误的回报。 它返回我“ 0”而不是我想要的ID。

你们知道为什么吗？

Answer 1

您准备好的语句永远不会执行，您应该添加execute：

$noteIdindice = $db->prepare("SELECT ID FROM indice WHERE Name = :Name");
$noteIdindice->bindParam(':Name', $name);
$noteIdindice->execute();//Add this row
$resultat = $noteIdindice->fetch();

编辑：

您正在尝试使用空值绑定参数。

        $stmtInd = $db->prepare("INSERT INTO indice(ID, Name, IDFormation)
        VALUES (:ID, :Name, :IDFormation)");
        $stmtInd->bindParam(':ID', $id);
        $stmtInd->bindParam(':Name', $name); //$name variable not exists
        $stmtInd->bindParam(':IDFormation', $idformation);//$idformation variable not exists

尝试这样做：

<?php
include 'Connection.php';

try { 
    $db = new PDO("$server:host=$host;dbname=$base", $user, $passwd); 
    //Indice 1
    $name = "Equilibre theorie / pratique";
    $idformation = "1";
    $valeur = $_POST["indice1"];
    $valeurtext = "";
    //Statement = INSERT INTO indice
    $stmtInd = $db->prepare("INSERT INTO indice(ID, Name, IDFormation)
        VALUES (:ID, :Name, :IDFormation)");
        $stmtInd->bindParam(':ID', $id);
        $stmtInd->bindParam(':Name', $name);
        $stmtInd->bindParam(':IDFormation', $idformation);
        $stmtInd->execute();
    //Statement = INSERT INTO note
    $stmtNote = $db->prepare("INSERT INTO note(ID, Valeur, Valeurtext, IDIndice)
        VALUES (:ID, :Valeur, :Valeurtext, :IDIndice)");
        $stmtNote->bindParam(':ID', $ID);
        $stmtNote->bindParam(':Valeur', $valeur);
        $stmtNote->bindParam(':Valeurtext', $valeurtext);
        $stmtNote->bindParam(':IDIndice', $IDindice);
        $stmtNote->execute(); 
    $noteIdindice = $db->prepare("SELECT ID FROM indice WHERE Name = :Name");
        $noteIdindice->bindParam(':Name', $name);
        $noteIdindice->execute();           
        $resultat = $noteIdindice->fetch(\PDO::FETCH_ASSOC);    
        var_dump($resultat);

    $IDindice = $resultat['ID'];

    echo "Success";
} 
catch (PDOException $e) { 
    die("Impossible de se connecter a la source de donnees..."); 
}
?>