javascript-返回带有唯一子项的父项，该子项与具有嵌套对象的对象数组中的给定搜索字符串匹配

Question

这是我先前提出的问题的跟进问题 。 从收到的答案中，我可以在一组对象的嵌套对象中进行搜索。

请以这个小提琴为例 。

var data = [
{
  'booking_name': 'gtec/1101822/lmikdy/ls-rmea/oss11',
  'asset_count': 2,
  'pdg': 'Invalid',
  'user_area': 'Invalid',
  'deployment_number': 'Invalid',
  'spoc': 'invalid',
  'release': 'Invalid',
  'start_date': '2017-06-12 00:00:00',
  'end_date': '2017-06-16 00:00:00',
  'asset_info': [
    {
      'bams_id': 'BAMS-1001423507',
      'hostname': 'GTVOSS11',
      'status': 10,
      'site_location': 'IEAT01 Tipperary',
      'rack_number': 'VIRTUAL RACK',
      'rack_u_position': 0,
      'manufacturer': 'EMC',
      'model': 'VM',

    },
    {
      'bams_id': 'BAMS-1001368001',
      'hostname': 'None',
      'status': 10,
      'site_location': 'IEAT01 Tipperary',
      'rack_number': 'VIRTUAL RACK',
      'rack_u_position': 0,
      'manufacturer': 'HP',
      'model': 'HP BL460C GEN8',

    }
],
'full_name': 'Invalid (invalid)',
'email_address': 'Invalid'
},
{
  'booking_name': 'gtec/1101822/lmikdy/ls-rmea/oss11',
  'asset_count': 2,
  'pdg': 'Invalid',
  'user_area': 'Invalid',
  'deployment_number': 'Invalid',
  'spoc': 'invalid',
  'release': 'Invalid',
  'start_date': '2017-06-12 00:00:00',
  'end_date': '2017-06-16 00:00:00',
  'asset_info': [
    {
      'bams_id': 'BAMS-1001423507',
      'hostname': 'GTVOSS11',
      'status': 10,
      'site_location': 'IEAT01 Tipperary',
      'rack_number': 'VIRTUAL RACK',
      'rack_u_position': 0,
      'manufacturer': 'EMC',
      'model': 'VM',

    }
],
'full_name': 'Invalid (invalid)',
'email_address': 'Invalid'
}];

在这里，当我搜索字符串'emc'时，该函数返回两个正确的对象。 但是作为“制造商”的“ emc”在子对象中。 并且每个子对象都不满足此条件。 我正在寻找的结果，例如'emc'，它应该返回2个父对象。 第一个父对象应该只有一个孩子（另一个孩子的制造商具有“ hp”）。 第二个父对象应该有一个孩子，因为它与搜索字符串匹配。

我试图用搜索结果创建一个新对象，但无法使其正常工作。

如何返回唯一满足给定搜索字符串的子对象的父对象？

这是我上一个问题的聊天记录 ，可以帮助您理解问题和要求。

Answer 1

您可以使用迭代和递归方法，如果子项与搜索值匹配，则返回检查结果并构建新的对象和数组。

 function getValue(item) { if (Array.isArray(item)) { return item.reduce(iterA, undefined); } if (item && typeof item === 'object') { return iterO(item); } if (typeof item !== 'object' && item.toString().toLowerCase().indexOf(search) !== -1) { return item; } } function iterO(o) { var temp = Object.keys(o).reduce(function (r, k) { var value = getValue(o[k]); if (value) { r = r || {}; r[k] = value; } return r; }, undefined); if (temp) { Object.keys(o).forEach(function (k) { if (!(k in temp)) { temp[k] = o[k]; } }); } return temp; } function iterA(r, a) { var value = getValue(a); if (value) { r = r || []; r.push(value); } return r; } var data = [{ booking_name: "gtec/1101822/lmikdy/ls-rmea/oss11", asset_count: 2, pdg: "Invalid", user_area: "Invalid", deployment_number: "Invalid", spoc: "invalid", release: "Invalid", start_date: "2017-06-12 00:00:00", end_date: "2017-06-16 00:00:00", asset_info: [{ bams_id: "BAMS-1001423507", hostname: "GTVOSS11", status: 10, site_location: "IEAT01 Tipperary", rack_number: "VIRTUAL RACK", rack_u_position: 0, manufacturer: "EMC", model: "VM" }, { bams_id: "BAMS-1001368001", hostname: "None", status: 10, site_location: "IEAT01 Tipperary", rack_number: "VIRTUAL RACK", rack_u_position: 0, manufacturer: "HP", model: "HP BL460C GEN8" }], full_name: "Invalid (invalid)", email_address: "Invalid" }, { booking_name: "gtec/1101822/lmikdy/ls-rmea/oss11", asset_count: 2, pdg: "Invalid", user_area: "Invalid", deployment_number: "Invalid", spoc: "invalid", release: "Invalid", start_date: "2017-06-12 00:00:00", end_date: "2017-06-16 00:00:00", asset_info: [{ bams_id: "BAMS-1001423507", hostname: "GTVOSS11", status: 10, site_location: "IEAT01 Tipperary", rack_number: "VIRTUAL RACK", rack_u_position: 0, manufacturer: "EMC", model: "VM" }], full_name: "Invalid (invalid)", email_address: "Invalid" }], search = 'emc', result = data.reduce(iterA, undefined); console.log(result); 

 .as-console-wrapper { max-height: 100% !important; top: 0; } 

Answer 2

我不确定您的方法需要走多深，但这应该可以解决问题

子项包含子项时，它将复制每一行，并且仅将集合替换为匹配值

 function filterSet(dataSet, matchFn) { return dataSet.reduce((current, row) => { if (typeof row === 'object') { for (let prop in row) { if (Array.isArray(row[prop])) { var set = filterSet(row[prop], matchFn); if (set && set.length > 0) { // copy the row, replace the array property with the results current.push( Object.assign({}, row, { [prop]: set } ) ); // since the full row is now in there // no need to check more break; } } else if (matchFn(row[prop])) { // copy not ref current.push( Object.assign( {}, row ) ); break; } } } return current; }, []); } var data = [{ 'booking_name': 'gtec/1101822/lmikdy/ls-rmea/oss11', 'asset_count': 2, 'pdg': 'Invalid', 'user_area': 'Invalid', 'deployment_number': 'Invalid', 'spoc': 'invalid', 'release': 'Invalid', 'start_date': '2017-06-12 00:00:00', 'end_date': '2017-06-16 00:00:00', 'asset_info': [{ 'bams_id': 'BAMS-1001423507', 'hostname': 'GTVOSS11', 'status': 10, 'site_location': 'IEAT01 Tipperary', 'rack_number': 'VIRTUAL RACK', 'rack_u_position': 0, 'manufacturer': 'EMC', 'model': 'VM', }, { 'bams_id': 'BAMS-1001368001', 'hostname': 'None', 'status': 10, 'site_location': 'IEAT01 Tipperary', 'rack_number': 'VIRTUAL RACK', 'rack_u_position': 0, 'manufacturer': 'HP', 'model': 'HP BL460C GEN8', } ], 'full_name': 'Invalid (invalid)', 'email_address': 'Invalid' }, { 'booking_name': 'gtec/1101822/lmikdy/ls-rmea/oss11', 'asset_count': 2, 'pdg': 'Invalid', 'user_area': 'Invalid', 'deployment_number': 'Invalid', 'spoc': 'invalid', 'release': 'Invalid', 'start_date': '2017-06-12 00:00:00', 'end_date': '2017-06-16 00:00:00', 'asset_info': [{ 'bams_id': 'BAMS-1001423507', 'hostname': 'GTVOSS11', 'status': 10, 'site_location': 'IEAT01 Tipperary', 'rack_number': 'VIRTUAL RACK', 'rack_u_position': 0, 'manufacturer': 'EMC', 'model': 'VM', }], 'full_name': 'Invalid (invalid)', 'email_address': 'Invalid' } ]; console.log(filterSet(data, (i) => { return i.toString().toLowerCase().indexOf('emc') >= 0; })); console.log(filterSet(data, (i) => { return i.toString().toLowerCase().indexOf('invalid') >= 0; }));