如何在python 2.4中通过urllib2提交帖子数据？

Question

我正在尝试使用json格式的数据提交POST请求，以使用Crowd API创建用户。

这是代码片段：

url = 'http://crowdserver/crowd/rest/usermanagement/1/user'
payload = '{"name": "sampleuser", "password": {"value": "secret"}, "active": true, "first-name": "Sample", "last-name": "User","display-name": "Sample User", "email": "sample@user.cool"}'
req = urllib2.Request(url, payload)
req.add_header('Content-type','application/json')
req.add_header("Accept", "application/json")
res = urllib2.urlopen(req)
output = resp.read()
print output
print resp.code

我得到以下输出：

Bad Request
Error code returned is 400

我认为这可能是编码问题，因此将有效负载替换为：

payload = json.dumps({"name": "sampleuser", "password": {"value": "secret"}, "active": true, "first-name": "Sample", "last-name": "User","display-name": "Sample User", "email": "sample@user.cool"})

哪个返回：

NameError: name 'true' is not defined

因此它看起来像"active": true的格式不可接受。

如果添加双引号，例如"active":"true" 则会收到TypeError ； TypeError: not a valid non-string sequence or mapping object

更新资料

因此，通过将active属性值设置为True确实解决了类型错误，但事实证明，由于invalid user data, for example missing password or the user already exists而已读the user already exists invalid user data, for example missing password or the user already exists返回了400错误-我觉得很奇怪输入无效的错误和现有用户共享相同的错误代码。

Answer 1

在这一行：

payload = '{"name": "sampleuser", "password": {"value": "secret"}, "active": true, "first-name": "Sample", "last-name": "User","display-name": "Sample User", "email": "sample@user.cool"}'

将..., "active": true, ...更改为..., "active": True, ...

Python的True / False区分大小写。