如何将这个查询构建为laravel雄辩

Question

我有这个查询

select est.*, bf.followup as bf_follow, bf.unidad as bf_unidad, bu.unidad as bu_unidad, bu.asistencia as bu_asistencia, bu.calificacion as bu_calificacion
from estudiantes as est
inner join bluecard as bc on bc.estudiante = est.usuario_id
inner join beneficiarios as bene on bene.usuario_creado = est.usuario_id
inner join (
    select bluecard, followup, unidad
    from bluecard_followups
    order by bf_id desc
) bf on (bf.bluecard = bc.bc_id)
left join (
    select bluecard, unidad, asistencia, calificacion 
    from bluecard_unidades
    order by bu_id desc
) bu on (bu.bluecard = bc.bc_id)

where bc.status = 1
group by est.usuario_id
limit 500

我知道如何用雄辩的方式进行联接，但是自定义联接我不知道如何编写。

有人发生过类似的事情吗？ 有没有人需要用laravel这样的查询？

帮帮我！ 谢谢

编辑

我这样运行查询：

$estudiantes = Estudiantes::select(
                            DB::raw("
               select est.*, bene.contrato as nro_contrato, bf.followup as bf_follow, bf.unidad as bf_unidad, bu.unidad as bu_unidad, bu.asistencia as bu_asistencia, bu.calificacion as bu_calificacion
              from estudiantes as est
              inner join bluecard as bc on bc.estudiante = est.usuario_id
              inner join beneficiarios as bene on bene.usuario_creado = est.usuario_id
              inner join (
              select bluecard, followup, unidad
              from bluecard_followups
              order by bf_id desc
              ) bf on (bf.bluecard = bc.bc_id)
              left join (
              select bluecard, unidad, asistencia, calificacion
              from bluecard_unidades
              order by bu_id desc
              ) bu on (bu.bluecard = bc.bc_id)

              where bc.status = 1
              group by est.usuario_id
              limit 500"))
                    ->get();

我得到了这个错误：

Answer 1

听起来您不需要加入，但需要工会 。 这样，您只需在单独的查询中执行当前的两个联接查询，然后使用并集函数将它们应用于另一个查询即可。