根据日期添加所有时间戳数据

Question

我有这个access_log表

create_time  | time_spent
--------------+------------
NOV 02, 2017  | 00:00:00
NOV 02, 2017  | 01:45:04
NOV 02, 2017  | 00:00:00
NOV 02, 2017  | 00:00:00
NOV 02, 2017  | 00:39:29
NOV 02, 2017  | 03:05:49
NOV 03, 2017  | 03:58:57
NOV 03, 2017  | 00:52:29
NOV 03, 2017  | 02:53:25

使用该表，使用PostgreSQL使它看起来像这样。 它应添加相应日期的所有time_spent列数据

create_time  | time_spent
--------------+------------
NOV 02, 2017  | 05:30:22
NOV 03, 2017  | 07:44:51

先感谢您。

Answer 1

一个简单的小组在这里：

t=# create table access_log (create_time  date,time_spent time);
CREATE TABLE
t=# copy access_log from stdin delimiter '|';
Enter data to be copied followed by a newline.
End with a backslash and a period on a line by itself, or an EOF signal.
>> NOV 02, 2017  | 00:00:00
NOV 02, 2017  | 01:45:04
NOV 02, 2017  | 00:00:00
NOV 02, 2017  | 00:00:00
NOV 02, 2017  | 00:39:29
NOV 02, 2017  | 03:05:49
NOV 03, 2017  | 03:58:57
NOV 03, 2017  | 00:52:29
NOV 03, 2017  | 02:53:25>> >> >> >> >> >> >> >>
>> \.
t=# select sum(time_spent), create_time from access_log group by create_time;
   sum    | create_time
----------+-------------
 05:30:22 | 2017-11-02
 07:44:51 | 2017-11-03
(2 rows)