如何概括Matlab函数？

Question

我有一个Matlab函数。 我需要对此功能进行概括。 此代码的目的是检查TableTemp中的IndicMP是否存在，然后提取相关的年龄限制，例如：Age_Limite_DC，Age_Limite_IT，Age_Limite_Ch和Transfert_Prime_IT_DC。 我的想法是泛化，传递参数以找出“ Type_pret”。（可能是我错了）由于我是Matlab的初学者，有人可以帮助我对可以在更通用的函数中使用的泛型函数进行编码背景？

function Structure = optimisation_function()

Data = load('Data.mat');

Structure = Data.Structure;
TableTemp = Data.TableTemp;


Age_Limite_DC          = zeros(size(Structure,1),1);
Age_Limite_IT          = zeros(size(Structure,1),1);
Age_Limite_CH          = zeros(size(Structure,1),1);
Transfert_Prime_IT_DC  = zeros(size(Structure,1),1);

for IndexMPAL = 1 : length(Structure.AnneeSouscription)

    % Determine Type_Pret (Loan Type)
    if ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'A'))
        Type_Pret = 'A';
    elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'B'))
        Type_Pret = 'B';
    elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'C'))
        Type_Pret = 'C';
    elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'D'))
        Type_Pret = 'D';
    elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'E'))
        Type_Pret = 'E';
    end
    MP_CP       = Structure.NomCodeProduit(IndexMPAL);
    MP_AnSous   = Structure.AnneeSouscription(IndexMPAL);
    MP_TypePret = Type_Pret;
    IndicCP     = strcmp(MP_CP, TableTemp.CodeProduit);
    IndicAS     = MP_AnSous== TableTemp.AnneeSouscription;
    IndicTP     = strcmp(MP_TypePret, TableTemp.TypePret);
    IndicMP     = IndicCP & IndicAS & IndicTP;        

    if ~any(IndicMP)
        Msg = strcat('CodeProduct:',MP_CP{1}, ', Année Souscription:', num2str(MP_AnSous), ', Type Prêt:', MP_TypePret);
        error('Error', Msg)
    else
        Age_Limite_DC(IndexMPAL,1) = TableTemp.Age_Limite_DC(IndicMP,1);
        Age_Limite_IT(IndexMPAL,1) = TableTemp.Age_Limite_IT(IndicMP,1);
        Age_Limite_CH(IndexMPAL,1) = TableTemp.Age_Limite_CH(IndicMP,1);
        Transfert_Prime_IT_DC(IndexMPAL,1)= 
        TableTemp.Transfert_Prime_IT_DC(IndicMP,1);
    end
end

Structure.Age_Limite_DC          = Age_Limite_DC;
Structure.Age_Limite_IT          = Age_Limite_IT;
Structure.Age_Limite_CH          = Age_Limite_CH;
Structure.Transfert_Prime_IT_DC  = Transfert_Prime_IT_DC;

end

Answer 1

if/elseif可以用单元格数组简化：

liststr = {'A','BB','C','D','E'}; % builds a cell array, each cell contains a string
Positive_matches = strfind(liststr,Structure.Type_Pret{IndexMPAL}) % returns a list for each cell of the indices where the element was found (empty if none)
Index = find(~cellfun('isempty', Positive_matches )) % converts the previous list into a logical 0/1 array indicating whether an item was found (1) or not (0)
% if isempty(Index); continue; end % If no index is found, to avoid an error in the next instruction, skips the rest of the code. 
Type_Pret = liststr(Index(1));

如果您的列表和Structure? , you can use的Type_Pret相同Structure? , you can use Structure? , you can use strcmp`：

liststr = {'A','B','C','D','E'};
if any(strcmp(Structure.Type_Pret,liststr))
    Type_Pret = Structure.Type_Pret
else
    % handle error
end

您也可以不使用Age_Limite_DC而直接在Structure.Age_Limite_DC上工作。