如何使学说不创建一个总是真实的场景？

Question

我正在尝试使用Doctrine比较日期时间值。

我有一个教义查询，看起来像这样：

$interval = new \DateInterval('PT'. 2 .'H');
$oldestAllowedDateTime = new \DateTime();
$oldestAllowedDateTime = $oldestAllowedDateTime->sub( $interval );

$queryBuilder = $repository->createQueryBuilder('pn');
$queryBuilder = $queryBuilder->select('notification')
  ->from('AppBundle\Entity\PushNotification','notification')
  ->where('pn.isSent IS NULL OR pn.isSent = 0')
  ->andwhere('pn.sendDate > :oldestAllowedDateTime')
  ->orderBy('pn.sendDate', 'DESC')
;
$queryBuilder->setParameter('oldestAllowedDateTime',$oldestAllowedDateTime);
$result = $queryBuilder->getQuery()->getResult();

...，它正在创建如下所示的SQL：

SELECT p0_.id AS id_0, 
p0_.content AS content_1, p0_.last_offset AS last_offset_2, 
p0_.failure_count AS failure_count_3, p0_.is_sent AS is_sent_4, 
p0_.send_date AS send_date_5 FROM push_notification p1_, 
push_notification p0_ WHERE (p1_.is_sent IS NULL OR p1_.is_sent = 0) 
AND p1_.send_date > ? ORDER BY p1_.send_date DESC

教义将返回所有记录，包括早于我指定的日期时间的记录。 从某种意义上讲，这是有道理的，因为Doctrine似乎正在建立一个涉及我要进行的时间戳比较的“总是真实的”方案。

有没有一种简单的方法可以使Doctrine只返回比我的oldestAllowedDateTime值新的记录？

====

编辑：这是我数据库中的send_date内容。

mysql> SELECT send_date FROM push_notification;
+---------------------+
| send_date           |
+---------------------+
| 2018-01-24 05:51:21 |
| 2018-01-24 11:44:30 |
+---------------------+
2 rows in set (0.00 sec)

Answer 1

您的代码看起来不错，请尝试下一个功能

// Inside your PushNotificationrRepository
public function getNotSentByDateInterval(\DateTimeInterval $interval)
{
    $from = (new \DateTime())->sub($interval);

    $qb = $this->createQueryBuilder('pn');
    $qb->where('pn.isSent IS NULL OR pn.isSent = 0')
      ->andWhere('pn.sendDate > :oldestAllowedDateTime')
      ->setParameter('oldestAllowedDateTime', $from)
      ->orderBy('pn.sendDate', 'DESC')
    ;

    return $qb->getQuery()->getResult();
}

这应该做的工作