使用sqlite3和python更新表

Question

我正在尝试使用sqlite3和python更新名为“ stats”的表。 该表具有[username, correct, total] 。 这是我正在使用的代码：

        conn = sqlite3.connect(stats_db)  # connect to that database (will create if it doesn't already exist)
        c = conn.cursor()  # make cursor into database (allows us to execute commands)
        outs = ""

        try:
            c.execute('''CREATE TABLE stats (username text,correct int, total int);''') # run a CREATE TABLE command
            outs = "database constructed"

        except:
            things = c.execute('''SELECT * FROM stats;''').fetchall()
            output_list = []
            for x in things:
                output_list.append(x)
            new_correct = output_list[0][1] + int(correct)
            new_total = output_list[0][2] + 1
            c.execute('''UPDATE stats SET correct = (?) and total = (?) where username = (?);''',(new_correct, new_total, username))

            things = c.execute('''SELECT * FROM stats;''').fetchall() #
            outs = "Things:\n"
            output_list = []
            for x in things:
                output_list.append(x)
            outs += str(output_list)
            conn.commit() # commit commands
            conn.close() # close connection to database
        return outs

但是，表中的值永远不会更新。 new_correct和new_total正确返回。 另外，有没有一种方法可以在不先调用先前值的情况下进行更新？ 我只需要将总数加1并根据0或1进行校正，具体取决于正确的输入是什么？

Answer 1

解决后，我必须将update命令中的and更改为逗号。 现在显示：

c.execute('''UPDATE stats SET correct = ?, total = ? where username = ?;''',(new_correct, new_total, username))