带有转义字符的JSON查询返回结果

Question

从以下查询中，我得到的结果为：

"Units": "[{\"Name\":\"Unit25\"}]",

查询如下重现此结果的查询，我简化了查询使用的实际查询，但基于选择是：

SELECT (      
SELECT *
  FROM (      
        SELECT
           JSON_QUERY(COALESCE((SELECT [Name] FROM (
                    SELECT [Name] 
                    FROM [TableA]                                                       
                    UNION 

                    SELECT TOP 3 [Name] 
                    FROM [TableB]) [T]
                    FOR JSON PATH),'[]')) AS [Units]
            FROM [User] [U]

               UNION

      SELECT
        JSON_QUERY(COALESCE((SELECT [Name] FROM (
                    SELECT [Name] 
                    FROM [TableA]                                                       
                    UNION 

                    SELECT TOP 3 [Name] 
                    FROM [TableB]) [T]
                    FOR JSON PATH),'[]')) AS [Units]
        FROM [Contact] [C]
         ) [Data] 
    FOR JSON PATH, INCLUDE_NULL_VALUES)

预期结果 ：

"Units": "[{"Name":"Unit25"}]",

如何实现？

Answer 1

这里的问题是，在UNION语句之前使用JSON_QUERY以某种方式破坏json的转义。 可能您可以使用JSON_QUERY作为最JSON_QUERY的语句来修复查询：

select JSON_QUERY(units) as Units from
(
    SELECT
        COALESCE((SELECT [Name] FROM (
                SELECT [Name] 
                FROM [TableA]                                                       
                UNION 

                SELECT TOP 3 [Name] 
                FROM [TableB]) [T]
                FOR JSON PATH),'[]')  AS [Units]
        FROM [User] [U]
           UNION
  SELECT
     COALESCE((SELECT [Name] FROM (
                SELECT [Name] 
                FROM [TableA]                                                       
                UNION 

                SELECT TOP 3 [Name] 
                FROM [TableB]) [T]
                FOR JSON PATH),'[]')  AS [Units]
    FROM [Contact] [C]
) u
FOR JSON auto, INCLUDE_NULL_VALUES

结果：