python（and or）中逻辑语句的组合

Question

我目前正在tkinter中制作石头，纸，剪刀射击游戏，并且正在尝试编写确定谁获胜的功能。 1 =石头，2 =纸，3 =剪刀。 该脚本不打印任何内容，除非comp == 2且choice == 1。

def Winning():
    if (((comp == 2) and (choice == 1)) or ((comp == 3) and (choice == 2)) or
        ((comp == 1) and (choice == 3))):
        messagebox.showinfo("Info", "YOU LOSE!!!")
    if (((choice == 2) and (comp == 1)) or ((choice == 3) and (comp == 2)) 
      or ((choice == 1) and (comp == 3))):
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "DRAW!!!")

Answer 1

我认为您是错误的方式。 假设我们必须使用数字输入，我会这样做：

ROCK, PAPER, SCISSORS = range(1, 4)

roshambo = {
    ROCK: SCISSORS,
    PAPER: ROCK,
    SCISSORS: PAPER
}

def Winning(comp, choice):
    if comp == choice:
        messagebox.showinfo("Info", "DRAW!!!")
    elif comp == roshambo[choice]:
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "YOU LOSE!!!")

这使您的逻辑清晰并简化了代码。 并且，它使扩展问题变得更加容易：

ROCK, PAPER, SCISSORS, LIZARD, SPOCK = range(1, 6)

roshambo = {
    ROCK: [LIZARD, SCISSORS],
    PAPER: [ROCK, SPOCK],
    SCISSORS: [PAPER, LIZARD],
    LIZARD: [SPOCK, PAPER],
    SPOCK: [SCISSORS, ROCK]
}

def Winning(comp, choice):
    if comp == choice:
        messagebox.showinfo("Info", "DRAW!!!")
    elif comp in roshambo[choice]:
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "YOU LOSE!!!")

字典是您的朋友，没有字典就不要编程！

Answer 2

您在哪里获得comp和choice ？

这样的事情会起作用：

from tkinter import messagebox

rock=1
paper=2
scissors=3


def Winning(comp, choice):
    if (((comp == 2) and (choice == 1)) or ((comp == 3) and (choice == 2)) or((comp == 1) and (choice == 3))):
        messagebox.showinfo("Info", "YOU LOSE!!!")
    if (((choice == 2) and (comp == 1)) or ((choice == 3) and (comp == 2)) or((choice == 1) and (comp == 3))):
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "DRAW!!!")


Winning(rock, paper)

这是你想要的吗 ？