Oracle SQL-具有多个标头的条件聚合枢纽

Question

这个问题是我以前的帖子的增强版本，希望我能在这里得到一些帮助。 我在下表/视图中有示例或虚拟数据：
TABLE / VIEW名称： CUST_HOTEL_VIEW

+----+----------------+---------------+---------------+--------+---------------+
| ID |    Customer    |     Hotel     | Booked_Status | Budget | Booked_Amount |
+----+----------------+---------------+---------------+--------+---------------+
|  1 | John Smith     | Beverly Hills | Booked        |   2000 |           500 |
|  2 | John Smith     | Royal Palms   | Cancelled     |   3000 |               |
|  3 | Marilyn Lawson | Beverly Hills |               |    500 |               |
|  4 | John Smith     | Ritz-Carlton  |               |    250 |               |
|  5 | Marilyn Lawson | Royal Palms   |               |    700 |               |
|  6 | Sarah Elliot   | Royal Palms   | Cancelled     |   1500 |               |
|  7 | Sarah Elliot   | Ritz-Carlton  | Booked        |   2000 |          1500 |
|  8 | Sarah Elliot   | Royal Palms   | Booked        |   2500 |          1000 |
+----+----------------+---------------+---------------+--------+---------------+

需要帮助以获取低于带有多个标题的输出，即获取客户数和每家酒店的预算总和（以下是excel数据透视表的输出）：

我正在使用Oracle 12c R1 db，如果我得到的条件聚合查询有帮助， 因为我发现这更简单，更容易理解。

我在下面的查询中尝试获取计数和预订量：

 SELECT COALESCE(CUSTOMER, 'Grand Total') as " " , (case when COUNT(booked_status) != 0 then count(booked_status) else null end) as "# Booked", sum(case when booked_status = 'Booked' THEN booking_amount ELSE null END) as "Booked Amount" FROM CUST_HOTEL_VIEW GROUP BY ROLLUP(CUSTOMER) order by CUSTOMER 

并得到以下输出：

 +--------------+----------+---------------+ | | # Booked | Booked Amount | +--------------+----------+---------------+ | John Smith | 1 | 500 | | Sarah Elliot | 2 | 2500 | | Grand Total | 3 | 3000 | +--------------+----------+---------------+ 

但是无法获得合并标头的输出。

我对此表示感谢。

谢谢，
Richa

更新：在下面添加最终输出表部分： 最终输出表：

 +--------------+---------------+--------+-------------+--------+--------------+--------+-------------+------+ | CUSTOMER | Beverly Hills | Royal Palms | Ritz-Carlton | Grand Total | +--------------+---------------+--------+-------------+--------+--------------+--------+-------------+------+ | | Count | Sum | Count | Sum | Count | Sum | Count | Sum | +--------------+---------------+--------+-------------+--------+--------------+--------+-------------+------+ | Sarah Elliot | 0 | (null) | 1 | 2500 | 1 | 2000 | 2 | 4500 | | John Smith | 1 | 2000 | 0 | (null) | 0 | (null) | 1 | 2000 | | Grand Total | 1 | 2000 | 1 | 2500 | 1 | 2000 | 3 | 6500 | +--------------+---------------+--------+-------------+--------+--------------+--------+-------------+------+ 

Answer 1

从问题的描述中，我无法推断出确切的要求是什么，但是在我看来，您正在寻找类似的东西：

---

演示： http : //sqlfiddle.com/#!4/dbd49/7

SELECT *
FROM (
  SELECT CUSTOMER, HOTEL, BUDGET
  FROM Table1
  WHERE BOOKED_STATUS = 'Booked'
)
PIVOT (
  count(*) as cnt, sum(BUDGET) as budget
  FOR HOTEL IN ('Beverly Hills','Royal Palms','Ritz-Carlton')
 )

---

|     CUSTOMER | 'Beverly Hills'_CNT | 'Beverly Hills'_BUDGET | 'Royal Palms'_CNT | 'Royal Palms'_BUDGET | 'Ritz-Carlton'_CNT | 'Ritz-Carlton'_BUDGET |
|--------------|---------------------|------------------------|-------------------|----------------------|--------------------|-----------------------|
| Sarah Elliot |                   0 |                 (null) |                 1 |                 2500 |                  1 |                  2000 |
|   John Smith |                   1 |                   2000 |                 0 |               (null) |                  0 |                (null) |